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3 years ago

Give two examples of steroids

1 answer:

3 0

Steroids are like hormones that greatly influences bodily activities mostly in growth and function. These functions may modify, change and control one’s body organs or system that’ll vary in form, shape or structure due to these hormone-like compounds and also, it can affect one’s psychological and neurological state. There are several types of steroids. Examples can include: 
1. Sex steroids. These are can influence reproduction and sex characteristics. 
2. Anabolic steroids. Most abused in many athletic activities. These steroids are used for muscle and bone growth.

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Reynolds number E. What is the mean velocity u. (ft/s) and the Reynolds number Re = pu., D/ for 35 gpm (gallons per minute) of w

Novay_Z [31]

Answer:

The mean velocity is 13 ft/s.

The Reynolds number is 88,583 and it is dimensionless.

Explanation:

We have water flowing in a pipe of 1.05 in diameter.

The density is ρ=62.3 lb/ft and the viscosity is 1.2 cP.

The mean velocity can be calculated as

$u=\frac{Q}{A}=\frac{Q}{\pi*D^2/4}=\frac{35gpm }{3.14*(1.05in)^2/4}\\\\ u=\frac{35}{0.865}*\frac{gal}{min}\frac{1}{in^2}*\frac{231in^3}{1gal}*\frac{1}{60s} \\\\ u=156\,in/s=13\,ft/s$

The Reynolds number now can be calculated for this flow as

$Re=\frac{\rho*u*D}{\mu}$

being ρ: density, u: mean velocity of the fluid, D: internal diameter of the pipe and μ the dynamic viscosity.

To simplify the calculation, we can first make all the variables have coherent units.

Viscosity

$\mu=1.2cP=\frac{1.2}{100}\frac{g}{cm*s}*\frac{1lb}{453.6g}*\frac{30.48cm}{1ft}= 0.0008\frac{lb}{ft*s}$

Diameter

$D=1.05in*(\frac{1ft}{12in} )=0.0875ft$

Then the Reynolds number is

$Re=\frac{\rho*u*D}{\mu}\\\\Re=62.3\frac{lb}{ft^3}*13\frac{ft}{s} *0.0875ft*\frac{1}{0.0008}*\frac{ft*s}{lb}\\\\Re=88,583$

8 0

3 years ago

Consider the following exothermic reaction and predict how the change below will affect the concentration (increase, decrease, s

aev [14]

Answer:

a) equilibrium shifts towards the left

b) equilibrium shifts towards the right hand side.

c)equilibrium shifts towards the left hand side

d) addition of argon has no effect on the equilibrium position

e) equilibrium position shifts towards the left hand side

f) equilibrium position is shifted towards the right hand side

g) addition of a catalyst has no effect on the equilibrium position

Explanation:

Given the equation;

3N2H4(g)⇄ 4NH3 (g) + N2 (g)

Adding N2

The addition of N2 will increase the concentration of N2 in the system thereby shifting the equilibrium position to the left in accordance with Le Chatelier's principle.

Removing N2

The removal of N2 drives the forward reaction and the equilibrium shifts towards the right yielding more N2 in accordance with Le Chateliers principle.

Add NH3

The addition of NH3 will shift the equilibrium position towards the left hand side according to Le Chateliers principle.

d) addition of argon has no effect on the equilibrium position.

e) increasing the temperature

Since the reaction is exothermic, increasing the temperature favours the reverse reaction and the equilibrium position his shifted towards the left hand side.

f) Decrease in volume;

Decreasing the volume favours the forward reaction hence the equilibrium position is shifted towards the right.

g) addition of a catalyst has no effect on the equilibrium position.

3 0

3 years ago

What energy is required for a reaction to occur?

kirza4 [7]

Answer:

B. Activation Energy

Explanation: A P E X

5 0

2 years ago

A chemist fills a reaction vessel with

FinnZ [79.3K]

Answer:

ΔG = -1366KJ/mol

Explanation:

The detailed step by step calculation is as shown in the attachment.

The relationship between ΔG, Temperature, gas constant and the reaction quotient was applied.

4 0

3 years ago

Give the characteristic of a second order reaction having only one reactant. Group of answer choices The rate of the reaction is

schepotkina [342]

Answer:

The rate of the reaction is proportional to the square of the concentration of the reactant.

Explanation:

Let us assume a hypothetical reaction in which the rate determining step is the elementary reaction;

2A------> A2

The rate of reaction will be given by:

Rate= k[A]^2

Hence for a second order reaction having only one reactant, the rate of reaction is proportional to the square of the concentration of the reactant. The proportionality constant k, is known as the rate constant of the reaction.

3 0

3 years ago