Answer:
A) amount of snowfall in a blizzard
Step-by-step explanation:
Both continuous and discrete data are quantitative.
The difference is that
- Continuous data can take any value. You obtain it by measurement.
- Discrete data can take only certain values. You obtain it by counting.
The amount of snowfall in a blizzard is continuous data. It can take any value such as 100.3 cm or 250.5 cm
.
B) is wrong. The number of students who pass a math quiz is discrete data. You can't have half a student.
C is wrong. The number of languages an individual speaks is discrete data. You can't speak half a language.
D) is wrong. The number or treadmills in a gym is discrete data. You can't have half a treadmill.
Well it's a dare so I guess I'll do it.
Answer:
C. 490.
Step-by-step explanation:
25% = 0.25.
If the number of emails that Ryan and Taylor each received is x emails then Sara received 2x + 0.25 * 2x = 2.5 emails.
So 2x + 2.5x = 882
x = 882/4.5
x = 196.
So Sara received 2.5 * 196
= 490 emails.
Answer:
<h2><u><em>
D</em></u></h2>
Step-by-step explanation:
You can first reduce this fraction by dividing both the numerator and denominator by the Greatest Common Factor of 549 and 999. I know that
61/111
is the same as
61÷111
Then using
Long Division for 61 divided by 111
and rounding to a Max of 4 Decimal Places gives me
=0.5495/.5495
<h3>then move the decimal point a digit to the <u><em>
RIGHT!!!!</em></u></h3>
Answer:
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Step-by-step explanation:
Given:
Length of diagonal = 9 in
Find:
Total length of iron needed to make the square frame and two diagonals.
Computation:
Area of square = 1/2(diagonal)²
Area of square = 1/2(9)²
Area of square = 40.5 in²
Area of square = Side × Side
40.5 in² = Side × Side
Side = 6.36 (approx)
Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 × diagonal)
⇒ (4 × 6.36) + (2 × 9)
⇒ (25.44) + (18)
⇒ 43.44 in
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
