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3 years ago

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Plot the points A(−2,−3) , B(−3,0) , C(3,2) , and D(4,−1) . What type of quadrilateral is ABCD ? Justify your answer using mid-p

oint, distance, slope and show your work for those you use.

1 answer:

Alika [10]3 years ago

6 0

Obtuse quadrilaateral. midpoint(-1,3) with slooe 1/2
distance 2

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Draw a model to write 2 3/5 as a improper fraction

Andreyy89

13/5
2 3/5
2x5=10
10+3=13
13/5

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3 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x^3x^-6)^2

allsm [11]

If the expression is what I understand it is, this is my answer. (x to the third times x to the negative sixth all squared)

First, i would simplify what is inside the parentheses. x^-6 is the equivalent to
1/x^6. Therefore, the expression inside the parentheses is a fraction: x^3/x^6.

When dividing numbers with exponents, just subtract the exponents.
3-6= -3 so the simplification of the expression in the parentheses is 1/x^3.

To finish the problem, I would apply the square from outside the parentheses to the values inside them. In this way, the exponent would be multiplied by 2.

Our final answer is 1/x^6.

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3 years ago

State the property that justifies the statement

cluponka [151]

Answer:

A. Subtraction Property of Equality

Step-by-step explanation:

3x + 4 = 10

Subtract 4 from both sides ---->Subtraction Property of Equality

3x + 4 - 4 = 10 - 4

3x = 6

So

If 3x + 4 = 10, then 3x = 6

Answer

A. Subtraction Property of Equality

7 0

3 years ago

Which expression can be used to check the answer to 56 divided by (negative 14) = n?

allochka39001 [22]

D because n= -14 and were dividing 56

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2 years ago

How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove

BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

$\dfrac{9}{n^2+1} =\dfrac{n+3}{4}$

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

$\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\$

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y

with 0 and solve for x. The graph of the equation is attached.

n ≈ 2.38450287

Hence, The equation has one extraneous solution which is n ≈ 2.38450287

For more information refer to the link.

brainly.com/question/15070282

5 0

2 years ago