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Sedaia [141]
3 years ago
7

PLEASE HELP!! 1 question 10 points

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0
67-27= 40
40 x 2= 80
just reverse the steps
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Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
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Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

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Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

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Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

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