Answer: for -10 + 4 the answer is -6
for -7 - 11 the answer is -18
Step-by-step explanation:
For -10+4 all you do is start at -10 and go up 4 to -6 (-9, -8, -7, -6)
and for -7 - 11 you start at 7 and just go down (but the numbers get bigger) to -18 (-8, -9, -10, -11, -12, -13, -14, -15, -16, -17, -18)
Step-by-step explanation:
I am not sure what you want to calculate as ultimate goal.
but your have an error already in your third line in the picture.
(3-6i)(2-4i) = 3×(2-4i) - 6i(2-4i)
you had there a "+" instead of a "-".
and then you made subsequent mistakes in every line, some of them are funnily bringing you more back to the real result (e.g. -12i + 12i would be 0 and not -24i, but if the third line would have been correct, then yes, -24i is actually needed) - but not completely.
= 3×2 - 3×4i - 6i×2 + 6i×4i =
= 6 - 12i - 12i + 24×-1 = 6 - 24i - 24 = -24i - 18
then in the last 3 lines you kind of lose it completely. I am absolutely not sure, what you are calculating, and where the "+" cube from instead of "×" (multiplications) and such.
(3+6i)(2+4i) = 3×2 + 3×4i + 6i×2 + 6i×4i =
= 6 + 12i + 12i + 24×-1 =
= 6 + 24i - 24 = 24i - 18
is that what you wanted to show ?
Answer: ![f^{-1}(x) = \frac{\sqrt[3]{x^{2}}}{x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D%7D%7Bx%7D)
<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and then solve for "y":


![y = \frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
![y = \frac{1}{\sqrt[3]{x}}*(\frac{\sqrt[3]{x}}{\sqrt[3]{x}})^{2}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%2A%28%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%7D%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%29%5E%7B2%7D)
![y = \frac{\sqrt[3]{x^{2}}}{x}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D%7D%7Bx%7D)
Answer:
its option B : 18x3 – 12x2 + 9x – 6
Step-by-step explanation:

Step-by-step explanation:
{9x+3y=-36
y=-3x-21
9x-9x-36=-36
y=-3x-21
x=0
y=-21