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3 years ago

Identify the contrapositive of the following statement. If x = 2, then x + 3 = 5.

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

4 0

Answer:

If x + 3 ≠ 5, then x ≠ 2 thus b: is your Answer

Step-by-step explanation:

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If f(x) = (x^2-36)/(x+6) is continuous at x = -6, find f(-6) a)-12 b)12 c)6 d)-6

NeTakaya

Answer:

Step-by-step explanation:

$f(x)=\dfrac{x^2-36}{x+6}= \\\\\\\dfrac{(x-6)(x+6)}{x+6}= \\\\\\(x-6) \\\\\\f(-6)=((-6)-6)=-12$

Therefore, the correct answer is choice A. Hope this helps!

7 0

3 years ago

Read 2 more answers

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

PLEASE HELP!!! I am stuck!

labwork [276]

1/3 has the largest value.

4 0

3 years ago

Read 2 more answers

Please take a look at the question. Please explain and type your explaination. Please make it quick as possible. Thankyou!

Firlakuza [10]

Answer:

Yes, it's true

Step-by-step explanation:

A fraction is a part of a whole number for example 1/2. 1/2 is a half of one whole piece and if you multiply it into any whole number whether it's 2,4,6,8,10...... basically, if you multiply a fraction less than one with a non-zero whole number, it will always be less than the whole number it's being cut into smaller pieces. However, if the fraction is greater than 1, we would technically have an answer greater than the whole number product, just something to remember.

5 0

3 years ago

Y=1/4 (x+2)(x – 6

gladu [14]

I have no idea I’m answering this because I need to ask more questions

4 0

2 years ago