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Tatiana [17]
3 years ago
14

What process would best separate a solution of liquid water and liquid rubbing alcohol

Chemistry
2 answers:
Ugo [173]3 years ago
7 0

Distillation is the answer, nothing else can separate these two substances unless you found a way to set it on fire

Flura [38]3 years ago
4 0
Chromatography A process use mixed liquid
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I need it done asap as fast as possible
Lubov Fominskaja [6]

Answer:

1. B

2. D. the form of a substance changes but not its identity

3. C

4. D

6 0
2 years ago
9. Describe two ways in which you can conserve and recycle lab resources.<br> I
Law Incorporation [45]

Answer:

Using solar energy, hydroelectric energy and wind are major ways of conserving natural resources. Trees and other organic energy sources are traditional sources of renewable energy. Forests can be replanted and hemp and other organic materials such as ethanol can be used to preserve natural resources.

4 0
2 years ago
1.What does the Law of Conservation of Energy tells us?
lorasvet [3.4K]
1. Energy can neither be created or destroyed.
2. Conduction. Putting a pot of water on a hot burner. Convection. Putting your wet shoes over an air vent to dry them quicker. Radiation. Sitting in front of the fire to warm your hands up.
3. renewable sources can be used again and again, but non renewable sources cannot.
4. I would recommend solar energy. I think solar energy should be considered because solar energy can be reused, and also because they can use it to power their houses and they wouldn't need fossil fuels to do so.
5. Turn off the lights and open the windows during the day and if something is left plugged into the wall and it is not being used, unplug it.

hope I could help!
4 0
3 years ago
1. Define fission and fusion. Give an example of fission and fusion reflecting in real life application.
Alja [10]

Answer :

  • Nuclear fission : In nuclear reaction, the nucleus of a larger atom breaks into two or more smaller nuclei. In fission process, protons and neutrons are produced and larger amount of energy is released.

Example : In nuclear power plant, the energy released from the process of nuclear fission which is converted into electrical energy that is used in our homes and factories.

  • Nuclear fusion : In nuclear reaction, the nuclei of two or more smaller atoms combine together to form single larger molecule. In fusion process, the mass of the resulting nuclei is more as compared to the starting nuclei and large amount of energy is also released.

Example : This process occurs in the sun and stars. In this, the isotopes of Hydrogen, Tritium and Deuterium combine together to form a neutron and a helium atom under high pressure and temperature.


4 0
2 years ago
How many moles of gas X are present if the gas has a volume of 2dm³ at room temperature and pressure? Give your answer to 2 deci
bezimeni [28]

Answer:

Approximately 0.08\; \rm mol, assuming that this gas is an ideal gas.

Explanation:

Look up the standard room temperature and pressure:25\; \rm ^{\circ}C and P = 101.325 \; \rm kPa.

The question states that the volume of this gas is V = 2\; \rm dm^{3}.

Convert the unit of all three measures to standard units:

\begin{aligned} T &= 25\; \rm ^{\circ}C \\ &= (25 + 273.15)\; \rm K \\ &= 293.15\; \rm K\end{aligned}.

\begin{aligned}P &= 101.325\; \rm kPa \\ &= 101.325 \; \rm kPa \times \frac{10^{3}\; \rm Pa}{1\; \rm kPa} \\ &= 1.01325 \times 10^{5}\; \rm Pa\end{aligned}.

\begin{aligned}V &= 2\; \rm dm^{3} \\ &= 2 \; \rm dm^{3} \times \frac{1\; \rm m^{3}}{10^{3}\; \rm dm^{3}} \\ &= 2 \times 10^{-3}\; \rm m^{3}\end{aligned}.

Look up the ideal gas constant in the corresponding units: R \approx 8.31\; \rm m^{3}\cdot Pa \cdot mol^{-1} \cdot K^{-1}.

Let n denote the number of moles of this gas in that V = 2\; \rm dm^{3}. By the ideal gas law, if this gas is an ideal gas, then the following equation would hold:

P \cdot V = n \cdot R \cdot T.

Rearrange this equation and solve for n:

\begin{aligned}n &= \frac{P \cdot V}{R \cdot T} \\ &\approx \frac{1.01325 \times 10^{5}\; {\rm Pa} \times 2 \times 10^{-3}\; {\rm m^{3}}}{8.31 \; {\rm m^{3} \cdot Pa \cdot mol^{-1} \cdot K^{-1}} \times 293.15\; {\rm K}} \\ &\approx 0.08\; \rm mol\end{aligned}.

In other words, there is approximately 2\; \rm mol of this gas in that V = 2\; \rm dm^{3}.

6 0
2 years ago
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