All categories

3 years ago

How many moles of H 2 can be formed if a 3.24 g sample of M g reacts with excess H C l ?

Chemistry

1 answer:

Ganezh [65]3 years ago

3 0

Answer:

0.135 mole of H2.

Explanation:

We'll begin by calculating the number of mole in 3.24 g of Mg. This can be obtained as follow:

Mass of Mg = 3.24 g

Molar mass of Mg = 24 g/mol

Mole of Mg =?

Mole = mass /Molar mass

Mole of Mg = 3.24/24

Mole of Mg = 0.135 mole

Next, we shall write the balanced equation for the reaction. This is illustrated below:

Mg + 2HCl —> MgCl2 + H2

From the balanced equation above,

1 mole of Mg reacted to produce 1 mole of H2.

Finally, we shall determine the number of mole of H2 produced by reacting 3.24 g (i.e 0.135 mole) of Mg. This can be obtained as follow:

From the balanced equation above,

1 mole of Mg reacted to produce 1 mole of H2.

Therefore, 0.135 mole of Mg will also react to produce 0.135 mole of H2.

Thus, 0.135 mole of H2 can be obtained from the reaction.

You might be interested in

You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y

lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = age of sample = 6 days

a = initial amount of the reactant = 1 g

a - x = amount left after decay process = 0.2 g

a) to find the rate constant

$6=\frac{2.303}{k}\log\frac{1.0}{0.2}$

$k=\frac{2.303}{6}\log\frac{1.0}{0.2}$

$k=0.268days^{-1}$

b) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days$

The half life is 2.58 days

3 0

3 years ago

How much of a 24-gram sample of Radium-226 will remain unchanged at the end of three half-life periods?

shutvik [7]

Answer:

The right answer is "3 g".

Explanation:

Given:

Initial mass substance,

$M_0=24 \ g$

By using the relation between half lives and amount of substances will be:

⇒ $M=\frac{M_0}{2^n}$

$=\frac{24}{2^3}$

$=3 \ g$

Thus, the above is the correct answer.

8 0

3 years ago

Living organisms all have dna and rna which are both

nadya68 [22]

They are both helix it is just that DNA has two and RNA has one

4 0

3 years ago

Read 2 more answers

Are elements considered to be substances?

Schach [20]

Answer:

C. Yes, because they have a definite composition.

Explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

7 0

3 years ago

What is the energy for each question in Joules?

beks73 [17]

Answer:

Hello, there!

In order to solve problems like this DO PEMDAS

The Exponent:

So, equals 4

Your problem becomes

Now we have to do what is in the (

( the is a )

And

Problem becomes

So, this means that your answer would be

Good luck on your assignment and enjoy your day!

kjExplanation:

7 0

2 years ago