BE and CD are parallel, so the triangles ABE and ACD are similar. Then the following relation holds:
AE/AD = AB/AC
10/(10 + 8) = x/(x + 6)
Solve for x :
10 (x + 6) = x (10 + 8)
10x + 60 = 18x
8x = 60
x = 60/8 = 7/5
Answer:
(3,1)
Step-by-step explanation:
Multiplying the second equation by 3, we get
-12x-6y=-42.
Now, adding this to the first equation, we get
-13x=-39
Therefore, x=3
plugging in x=3 to the first equation, we get that
-3+6y=3
adding 3 to both sides,
6y=6
therefore, y=1
The key to this question is calculating the percentage of students within each category (honor roll or non-honor roll) who received the class requested. We need to calculate the ratio of students who received the class they requested and who did not for both honor roll and non-honor roll students :
Honor Roll :
215 + 80 = 295 total honor roll students
215/295 = 72.88% = percentage of honor roll students who received class requested
80/295 = 27.12% = percentage of honor roll students who did not receive class requested
Non-Honor Roll :
125 + 80 = 205 total non-honor roll students
125/205 = 60.98% = percentage of non-honor roll students who received class requested
80/205 = 39.02% = percentage of non-honor roll students who did not receive class requested
72.88% of honor roll students received the preferred class as opposed to only 60.98% of non-honor roll students. Therefore, there is an advantage.
The handshake is an illustration of combination, and the values of n and r are 21 and 2, respectively
<h3>How to determine the values of n and r?</h3>
The number of students in the class is 21.
This represents the value of n
i.e. n = 21
Each student shakes hand with another student (i.e. 2 students per handshake)
This represents the value of r
i.e. r = 2
Hence, the values of n and r are 21 and 2, respectively
Read more about combination at:
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