Answer:
A
Step-by-step explanation:
3x+4(3x+6)= 15x+24
distribute 4(3x+6)
which equals 12x+24
3x+12x+24= 15x+24
Now combine like terms
15x+24= 15x+24
its equal so BOOM .
For this case we have the following system of equations:
We can Rewrite the system of equations of the form:
Where,
A: coefficient matrix
x: incognita vector
b: vector solution
We have then:
![A=\left[\begin{array}{ccc}5&3\\-8&-3\end{array}\right]](https://tex.z-dn.net/?f=%20A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%263%5C%5C-8%26-3%5Cend%7Barray%7D%5Cright%5D%20%20)
![x=\left[\begin{array}{ccc}x\\y\end{array}\right]](https://tex.z-dn.net/?f=%20x%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%20)
![b=\left[\begin{array}{ccc}17\\9\end{array}\right]](https://tex.z-dn.net/?f=%20b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D17%5C%5C9%5Cend%7Barray%7D%5Cright%5D%20%20)
Then, the determinant of matrix A is given by:
Answer:
The determinants for solving this linear system are:
Answer:
432 in^2
Step-by-step explanation:
in similar quadrilaterals, the first point of one quad. corresponds to the first point of the other quad, so in this case UA corresponds with CH.
since CH is 3/4 the length of UA, we can also assume that the other sides in ZUCH are 3/4 the length of their corresponding sides in SQUA.
even though we don't know what quadrilateral SQUA and ZUCH are, we know the area of SQUA is 9/16 times less than ZUCH.
want some proof?
lets say SQUA and ZUCH are rectangle/square
ZUCH: 4X4 = 16
SQUA: 3X3 = 9
now lets say they are trapezoids. We will set ZUCH 2nd base to 8 and height to 16, therefore SQUA bases will be 3 and 6, and the height will be 12 (multiply ZUCH lengths by 3/4)
ZUCH = (b1+b2)(h)/2 = (4+8)(16)/2 = 96
SQUA = (b1+b2)(h)/2 = (3+6)(12)/2 = 54
simplify 96/54 = 16/9
now we can multiply 243 by our factor 16/9 to find the area of SQUA.
243 * 16/9 = 432 in^2
Answer:
1/3
Step-by-step explanation:
There are 6 numbers on a dice, you want one out of the 2 outcomes, so tat makes it 2/6 or 1/3 chance of rolling a 3, or a 5
39/1.5=26 for the 1.5 hours difference.
divide 26/2=13 for each person.
divide 4/2 for the speed increase of person north. The speeds much average to 13.
subtract 13-2=11 and add 13+2=15 for south and north.
north speed is 15 km per hour and south is 11 km per hour.
