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olya-2409 [2.1K]
3 years ago
5

Solve this system of linear equations. Separate the x and the y values with a comma.

Mathematics
1 answer:
ohaa [14]3 years ago
4 0
4x = -60 - 19y
-7x = -48 - 19y

Subtract the bottom equation from the top:
4x + 7x = -60 + 48 - 19y + 19y

Simplify:

11x = -12 -0y
11x = -12

Divide both sides by 11:
11x/11 = -12/11

Simplify:
x = -12/11
Then plug in x to solve for y: 4(-12/11) = -60 - 19y

Simplify: -48/11 = -60 - 19y

Add 60 to both sides (keep in mind 60 = 660/11):

-48/11 + 660/11 = -60 + 60 - 19y

Simplify:
612/11 = 0 - 19y
612/11 = -19y

Divide both sides by -19 (keep in mind that dividing by -19 is the same as multiplying by -1/19):
612/11 • -1/19 = -19y/-19

Simplify:
-612/209 = y
y = -612/209

So, the answer is: (-12/11, -612/209)
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In 1928, when the high jump was first introduced as a women's sport at the Olympic Games, the winning jump for women was 70.0 in
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Answer: year 2194



Explanation:



1) Model the jump of the women:


i) initial jump = 70.0 in


ii) increase rate = 0.48% per year


iii) equation: h = 70.0(1 +0.0048)ⁿ


2) Model the jump of the men:


i) initial jump 86.5 inches.


ii) increase rate, 0.4%.


iii) equation: h = 86.5 (1 + 0.004)ⁿ


3) Equal the two equations (h = h) to find when the jumps will be equal:


i) 70.0(1 +0.0048)ⁿ = 86.5 (1 + 0.004)ⁿ


ii) 70.0(1.0048)ⁿ = 86.5 (1.004)ⁿ


ii) [1.0048ⁿ / 1.004ⁿ] = 86.5/70.0


iii) [1.0048/ 1.0040]ⁿ = 86.5/70.0


iv) n log (1.0048 / 1.0040) = log ( 86.5/70)


v) n = log (86.5/70) / log (1.0048/1.0040) ≈ 266


3) year = 1928 + 266 = 2194


That is in the year 2194

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