Well, we can denote L and W for the length and width respectively. Lets say the A is the area, we have: 1. A=(L × W) as well as 2. 2(L+W)=400. We rearrange the second equation to get 3. W=200-L. From this, we can see that 0<L<200. Substitute the third equation into the first to get A=(200L-L²). put this formula into the scientific calculator and you will find a parabola with a maximum. That would be the maximum area of the enclosed area. Alternatively, we can say that L is between 0 and 200 when the area equals 0. (The graph you find will be area against length). As the maximum is generally found halfway, we substitute 100 into the equation and we end up with 10000.
Hope this helps.
Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.
Num days late = 0.8 * 30=24
So Deborah was late 24 out of 30 working days. Would appreciate a brainliest
Answer:
395.85
Step-by-step explanation:
If the diameter is 12, then the radius must be 6. Following the formula of pi: 2 * pi * radius, our result is 37.7. 37.7 * 10.50 is 395.85
I really hope this helps. My memory of circles and pi isn't the best.
Answer: 80 feet.
Step-by-step explanation:
1. As you can see in the figure, triangle ABC and the triangle DFG are similar.
2. The scale of factor of triangle ABC to triangle DFG is the following:
3. Therefore, the lenght of the side DG of the trinagle DFG is:
4. The perimeter of the triangle DFG is:
5. Therefore, she would need 80 feet of fence.
