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klio [65]
3 years ago
7

2/3j=8 HURRY UP I HAVE A QUIZ

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

J=12

Step-by-step explanation:

(2/3)*j = 8 // - 8

(2/3)*j-8 = 0

2/3*j-8 = 0 // + 8

2/3*j = 8 // : 2/3

j = 8/2/3

j = 12

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Peter threw the football 72 feet. How many yards did he throw the football ?
Darya [45]

1 yard = 3 feet.

Divide total feet by 3 to get yards:

72 feet / 3 = 24 yards.

3 0
3 years ago
2. BT bisects ZABC. MZABT = 4x-16 and m CBT = 2x + 6 Find MZABT.
Paladinen [302]

Answer:

The measure of angle ABT is 28°

Step-by-step explanation:

* Lets revise the bisector of a angle

- If a ray bisects and angle that mean the ray divide the angle into

 two equal parts in measure

- Ex: if the ray BD bisects angle ABC, then the measure of angle ABD is

 equal to the measure of angle CBD

* Lets solve the problem

∵ BT bisects ∠ABC

∴ m∠ABT = m∠CBT

∵ m∠ABT = 4x - 16

∵ m∠CBT = 2x + 6

- Equate the two values

∴ 4x - 16 = 2x + 6

- Lets solve the equation by subtracting 2x from both sides and

 adding 16 to both sides

∴ 4x - 2x = 6 + 16

∴ 2x = 22 ⇒ divide both sides by 2

∴ x = 11

- Lets find the measure of angle ABT

∵ m∠ABT = 4x - 16

- Substitute x by 11

∴ m∠ABT = 4(11) - 16 = 44 - 16 = 28°

* The measure of angle ABT is 28°

6 0
3 years ago
Karls mother buys 60 party favors to give out as a fift during karls birthday party which number of guest will not let her divid
xeze [42]
THE answer is 15 just look it up

7 0
3 years ago
Read 2 more answers
H(x)=1/8x^3-x^2<br><br> Over which interval does h have a positive average rate of change?
lara31 [8.8K]

Answer:

(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}

Step-by-step explanation:

h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \  respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x

For positive rate of change h'(x)>0

\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\

6 0
3 years ago
The areas of 10 cities are given in the table.
Masteriza [31]
The range for the cities in the south is 145 larger than the range for the cities in the north.

We find the range by subtracting the highest and lowest values; in the North, we have:
305 - 58 = 247

In the South, we have:
503 - 111 = 392

The difference in the ranges is 392 - 247 = 145.
5 0
3 years ago
Read 2 more answers
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