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Vika [28.1K]
3 years ago
11

Consider the population consisting of all computers of a certain brand and model, and focus on whether a computer needs service

while under warranty.
a. Pose several probability questions based on selecting a sample of 100 such computers.

b. What inferential statistics question might be answered by determining the number of such computers in a sample of size 100 that need warranty service?
Mathematics
1 answer:
eimsori [14]3 years ago
7 0

Answer and explanation:

A. What is the probability that more than half of the sample of 100 computers would need warranty service?

What is the probability that more than half of the sample of 100 computers would not need warranty service?

What is the probability that out of sample of 100 more than 20% would require warranty service?

B. If our sample of 100 computers of that brand and model reveals that 30 computers need warranty service, does this give a valid conclusion that all such computers in the population would require about 30% warranty service or less?

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A boiler has five identical relief valves. The probability that any particular valve will open on demand is 0.93. Assume indepen
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Answer:

There is a 99.99998% probability that at least one valve opens.

Step-by-step explanation:

For each valve there are only two possible outcomes. Either it opens on demand, or it does not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 5, p = 0.93

Calculate P(at least one valve opens).

This is P(X \geq 1)

Either no valves open, or at least one does. The sum of the probabilities of these events is decimal 1. So:

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.93)^{0}.(0.07)^{5} = 0.0000016807

Finally

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000016807 = 0.9999983193

There is a 99.99998% probability that at least one valve opens.

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3 years ago
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the answer is:

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1 point
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Answer: 2x-y=15

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Answer:

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Step-by-step explanation:

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If we refer to the longest side as x and the shortest side as y and the medium side as z then we come up with this formation:

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