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MrRa [10]
4 years ago
12

Read the attachment below BEST ANSWER WILL RECIEVE BRAINLIEST

Mathematics
1 answer:
miv72 [106K]4 years ago
5 0

Answer:

G Q = 25


Explanation:

As  Q  is the midpoint of  G H , we have  G Q = Q H  and  G H = G Q + Q H = 2 × G Q

Now as  G Q = 2 x + 3 , and  G H = 5 x − 5 , we have  5 x − 5 = 2 × ( 2 x + 3 )  or  5 x − 5 = 4 x + 6  or  5 x− 4 x = 6 + 5  i.e.  x = 11  

Hence,   G Q = 2 × 11 + 3 = 22 + 3 = 25

hope this helps!!!!!!!!!!!

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How much material is needed to construct a triangular tent that is 6 feet wide 4 feet tall and 8 feet long with side measurement
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Answer: 152ft^2

The amount of material needed to construct the tent is 152ft^2

Step-by-step explanation:

The amount of material needed to construct a triangular tent= the surface area of the triangular tent.

S.A = area of the 2 side rectangles + area of the 2 side triangles + area of the base.

S.A = Ab + At + Ar ....1

Area of the base Ab= Length × width = 8×6 = 48ft^2

Area of the two triangles At = 2 × 0.5 × width × height

At = width × height = 6×4 = 24ft^2

Area of the two rectangles Ar = 2 × side measurement × length

Side measurement is given as 5ft.

or it can be calculated using;

Side length can be calculated using Pythagoras theorem.

Examining the figure attached, we can see that;

Side breadth b = √(h^2 + (w/2)^2)

b = √(4^2 + (6/2)^2) = √(16+9) = √25

b = 5ft

Ar = 2×5×8 = 80ft^2

From eqn1, S.A can be solved as;

S.A = 48 + 24 + 80

S.A = 152ft^2

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