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harina [27]
3 years ago
7

Katy chose a card at random from a deck of 52 cards. Katy replaced the first card and then chose a second card. What is the prob

ability that Katy chose a diamond both times?
A). 1/16
B). 1/52
C). 1/169
D). 1/208
Mathematics
2 answers:
Alisiya [41]3 years ago
5 0
52 total cards....13 total diamonds in the deck

P(1st card picked being a diamond) = 13/52
replacing the card, so the sample space remains the same
P(2nd card being a diamond) = 13/52

P(both) = 13/52 * 13/52 = 169/2704 = 1/16 <==

Paladinen [302]3 years ago
5 0
Any suit is a quarter of the deck, or 13 cards out of 52, so with replacement the probability of picking two straight of any suit is the same.

P(DD)=(1/4)(1/4)

P(DD)=1/16
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PLEASE HELP ME IT'S DUE TODAY AND IT COULD HELP MY GRADE A LOT
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Answer:

c = 13

m∡A = 60°

m∡B = 30°

Step-by-step explanation:

This is a 5-12-13 triangle. However, to make sure, I will put the steps.

Allow for each sides to be denoted as a-b-c, in which c is the hypotenuse (longest side). Set the equation:

a² + b² = c²

Plug in the corresponding numbers to the corresponding variables:

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Note the equal sign, what you do to one side, you do to the other. Isolate the variable, c, by rooting both sides:

√c² = √169

c = √169 = √(13 * 13) = 13

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13 is your answer for c.

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