Standard form for circle with radius r and center (h,k) is
(x-h)^2+(y-k)^2=r^2
r=36
center at -2,-7
(x-(-2))^2+(y-(-7))^2=36^2
(x+2)^2+(y+7)^2=1296
firts option
Answer:
y=x+20
Step-by-step explanation:
we have to find the slope
y2-y1/x2-x1
3-2/23-22
1/1
y=1x+b
y-22 = 1(x-2) + b
y=x+20
Perpendicular lines have slopes that are negative reciprocals of each other, so the equation of the line in point-slope form is:

Rewriting this in standard form,
