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2 years ago

What is the area of the circle whose equation is (x − 9)2 + (y − 3)2 = 64?

Mathematics

1 answer:

aalyn [17]2 years ago

7 0

(x-xo)²+(y-yo)²=r²
(x-9)²+(y-3)²=64
r²=64
Area of a circle=πr²=3.14×64=200.96

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2 years ago

Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger

Andre45 [30]

Answer:

The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

Step-by-step explanation:

Let the three consecutive odd integers be: $x-2,x\ and \ x+2$

The condition given is:

$4[x-2+x+x+2]=3x(x+2)-765$

Solve this for <em>x</em> as follows:

$4[x-2+x+x+2]=3x(x+2)-765\\4\times 3x=3x^{2}+6x-765\\3x^{2}-6x-765=0\\x^{2}-2x-255=0\\x^{2}-17x+15x-255=0\\x(x-17)+15(x-17)=0\\(x-17)(x+15)=0$

If $(x-17)=0$ then the value of <em>x</em> is 17.

The odd numbers are:

$x-2=17-2=15\\x=17\\x+2=17+2=19$

If $(x+15)=0$ then the value of <em>x</em> is -15.

The odd numbers are:

$x-2=-15-2=-17\\x=-15\\x+2=-15+2=-13$

Thus, the consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

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2 years ago

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