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natulia [17]
3 years ago
6

I need help with this math challenge! Please

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
8 0

i need to see what problem your doing and then i can totally help you!!!!

tester [92]3 years ago
6 0
If I've understood this correct, n bisects (cuts in half) the 44yd line? So we get a triangle like this and perform pythagorus theorem.

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Can you please help me with#11?I'm not sure how to find the answer.​
almond37 [142]

Answer:

You need to find the x and y intercepts so...

The x intercept is (18,0) since x=18

The y intercept is (0,12) since y=12

Step-by-step explanation:

Cover the y when you are finding the y intercept

Cover the x when you are finding the x intercept

8x/8

144/8

=18

12y/12

144/112

=12

5 0
3 years ago
Help me out please, thanks.
Afina-wow [57]

Answer:

The answer is 675.75

Step-by-step explanation:

159 × 4.25= 675.75

8 0
3 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
4 years ago
Find three ratios that are equivalent to 20:25
V125BC [204]

Answer:

4/5 , 40/50, 80/100

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
HELP ME ON GEOMETRY!!! PLZ<br> NO LINKS! &gt; i will report.
DiKsa [7]

Answer

I believe B.)8in3 is the right answer according to the square-cube law.

Step-by-step explanation:

3 0
3 years ago
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