To start, let x represent the width and x+100 represent the length.
Since the perimeter of a figure is the sum of all the measurements of the side which can be represented by (x+100)+(x+100)+x+x and since you know your perimeter is 960 feet, you can set the expression equal to 960. This would look like this:
(x+100)+(x+100)+x+x=960
Once you have done that, combine any like terms (combine terms with the same variables and raised to the same power together) which would simplify to this:
4x+200=960
Now that you have your like terms simplified, subtract 200 from both sides to get 4x=760 and finally, to solve for x, or find the width, divide both sides by 4 to get x=190.
Now that you have your width, now you must find your length as the question asks to find the dimensions of the rectangular field. To find the length, add 100 to the width of (190) since according to the information given, the length is 100 more than the width. When you add 100 to 190, you should get that your length is 290.
Now that you have your length and width, you can conclude that the dimensions of the field is 190 by 290 feet, which is your answer :)
Answer:
answer of your questions
Step-by-step explanation:
The process of obtaining the equation is similar, but it is more algebraically intensive. Given the focus (h,k) and the directrix y=mx+b, the equation for a parabola is (y - mx - b)^2 / (m^2 +1) = (x - h)^2 + (y - k)^2.
Answer:
Do you mean which equation should the 5x+10=15 be multiplied to?
it would be -2
Step-by-step explanation:
This is because 5 times -2 is -10
and so when you add the (now) x value of the first equation to the x value of the second equation, it gets 0
which makes it eliminated!
-10x+10x=0
Given,
Rate of free fall = 216 km/h
Solution,
km/h to m/s is converted as follows :
So, the rate of fall is 60 m/s.
If t = 20 s
Assume, initial velocity = 0
It will move under the action of gravity.
Using equation of motion,
Hence, this is all for the solution.
28 divided by 4 = 7
so do 7 * 5 which is 35 so they make 35 cookies in 5 seconds
