Answer:
500 nm
Explanation:
In this problem, we have a diffraction pattern created by light passing through a diffraction grating.
The formula to find a maximum in the pattern produced by a diffraction grating is the following:
where:
d is the distance between the lines in the grating
is the angle at which the maximum is located
m is the order of the maximum
is the wavelength of the light used
In this problem we have:
is the angle at which is located the 2nd-order bright line, which is the 2nd maximum
n = 5000 lines/cm is the number of lines per centimetre, so the distance between two lines is
Re-arranging the equation for , we find the wavelength of the light used:
Heya!
For this problem, use the formula:
s = Vo * t + (at^2) / 2
Since the initial velocity is zero, the formula simplifies like this:
s = (at^2) / 2
Clear a:
2s = at^2
(2s) / t^2 = a
a = (2s) / t^2
Data:
s = Distance = 518 m
t = Time = 7,48 s
a = Aceleration = ¿?
Replace according formula:
a = (2*518 m) / (7,48 s)^2
Resolving:
a = 1036 m / 55,95 s^2
a = 23,34 m/s^2
The aceleration must be <u>23,34 meters per second squared</u>
To solve this problem we will apply the concepts related to energy conservation. Here we will understand that the potential energy accumulated on the object is equal to the work it has. Therefore the relationship that will allow us to calculate the height will be
Here,
m = mass
g = Acceleration due to gravity
h = Height
our values are,
Replacing,
Then the height is 32.83m.
Well first of all, when it comes to orbits of the planets around
the sun, there's no such thing as "orbital paths", in the sense
of definite ("quantized") distances that the planets can occupy
but not in between. That's the case with the electrons in an atom,
but a planet's orbit can be any old distance from the sun at all.
If Mercury, or any planet, were somehow moved to an orbit closer
to the sun, then ...
-- its speed in orbit would be greater,
-- the distance around its orbit would be shorter,
-- its orbital period ("year") would be shorter,
-- the temperature everywhere on its surface would be higher,
-- if it has an atmosphere now, then its atmosphere would become
less dense, and might soon disappear entirely,
-- the intensity of x-rays, charged particles, and other forms of
solar radiation arriving at its surface would be greater.
<span>The process shown in this diagram contributed great amounts of heat to the young planet Earth and is best known as radioactive
decay. Decay is known to release large amounts of heat. </span>
