Question

How high will a 0.345 kg rock go if thrown straight up by someone who does 111 J of work on it? Neglect air resistance.

Answer 1

To solve this problem we will apply the concepts related to energy conservation. Here we will understand that the potential energy accumulated on the object is equal to the work it has. Therefore the relationship that will allow us to calculate the height will be

$W = PE$

$W = mgh$

Here,

m = mass

g = Acceleration due to gravity

h = Height

our values are,

$m = 0.345 kg$

$g = 9.8m/s^2$

$W = 111J$

Replacing,

$W =mgh$

$111 = (0.345)(9.8)h$

$h = 32.83m$

Then the height is 32.83m.