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2 years ago

A bus driver heads south with a steady speed of

Physics

1 answer:

Nutka1998 [239]2 years ago

5 0

ANS

{ A }

Magnitude

$5400.097 \: ✓ \: m$

Direction

$25.52 \: ✓ \: ° South \: of \: West$

{ B }

Average speed in ( m/s )

$23.43 \: ✓ \: m/s$

{ C }

Magnitude

$14.06 \: ✓ \: m/s$

Direction

$25.52 \: ✓ \: ° South \: of \: West$

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What happens when a mechanical wave travels through a medium?

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If a mass of .343 kg moves down a 5m ramp in 5.8 seconds, what is the velocity and KE developed by the moving mass

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Velocity 0.86m/s

0.13J

Explanation:

Given parameters:

Mass = 0.343kg

distance = 5m

time taken = 5.8s

Unknown:

Velocity of mass = ?

Kinetic energy = ?

Solution:

Velocity is the rate of change of displacement with time. It is a vector quantity that shows magnitude and direction.

Mathematically;

Velocity = $\frac{displacement}{time}$

Velocity = $\frac{5}{5.8 }$ = 0.86m/s

Kinetic energy is the energy due to the motion of a body. It is expressed mathematically as:

Kinetic energy = $\frac{1}{2} m v^{2}$

m is the mass

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Kinetic energy = $\frac{1}{2 } x 0.343 x 0.86^{2}$ = 0.13J

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3 years ago

Write one example of a physical change and one example chemical change

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Physical change = changes the physical properties (more commonly known as it's look)
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A runner begins from rest at the starting line and travles for 6.5 seconds, a runner reaches a speed of 13.4 m/s what is the run

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The acceleration of the runner in the given time is 2.06m/s².

Given the data in the question;

Since the runner begins from rest,

Initial velocity; $u = 0$

Final velocity; $v = 13.4m/s$

Time elapsed; $t = 6.5s$

Acceleration of the runner; $a = \ ?$

<h3>Velocity and Acceleration</h3>

Velocity is the speed at which an object moves in a particular direction.

Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion

$v = u + at$

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

To determine the acceleration of the runner, we substitute our given values into the equation above.

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Therefore, the acceleration of the runner in the given time is 2.06m/s².

Learn more about Equations of Motion: brainly.com/question/18486505

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