Answer:
θ = 1.591 10⁻² rad
Explanation:
For this exercise we must suppose a criterion when two light sources are considered separated, we use the most common criterion the Rayleigh criterion that establishes that two light sources are separated census the central maximum of one of them coincides with the first minimum of the other source
Let's write the diffraction equation for a slit
a sin θ = m λ
The first minimum occurs for m = 1, also field in these we experience the angles are very small, we can approximate the sin θ = θ
θ = λ / a
In our case, the pupil is circular, so the system must be solved in polar coordinates, so a numerical constant is introduced.
θ = 1.22 λ / D
Where D is the diameter of the pupil
Let's apply this equation to our case
θ = 1.22 600 10⁻⁹ / 0.460 10⁻²
θ = 1.591 10⁻² rad
This is the angle separation to solve the two light sources
Answer:
The correct answer is the second option
Explanation:
The formula in question (for gravitational force) is provided below
F = G.m₁.m₂/r²
Where
F = force of gravity
G = gravity constant (6.674 × 10⁻¹¹ m.kg⁻¹.s⁻²)
m₁ and m₂ = are the masses of the objects
r² = distance between the centers of the two objects
From the above, <u>it can be deduced that m₁ and m₂ are masses and hence can only be positive. Positives multiplied together only gives positive, thus the second option is correct.</u>
Cm2 it is unit of area not volume
