Explanation:
The U.S. launched its first man into space in May 1961.
We can solve the problem by using Newton's second law of motion:
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object
In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
![a= \frac{F}{m}= \frac{1050 N}{760 kg}=1.4 m/s^2](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7BF%7D%7Bm%7D%3D%20%5Cfrac%7B1050%20N%7D%7B760%20kg%7D%3D1.4%20m%2Fs%5E2%20%20)
The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
<span>
B) 1.4 m/s2 horizontally.</span>
Answer:
48.16 %
Explanation:
coefficient of restitution = 0.72
let the incoming speed be = u
let the outgoing speed be = v
kinetic energy = 0.5 x mass x ![x velocity^{2}](https://tex.z-dn.net/?f=%20x%20velocity%5E%7B2%7D)
- incoming kinetic energy = 0.5 x m x
- coefficient of restitution =
![\frac{v}{u}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%7D%7Bu%7D)
0.72 =![\frac{v}{u}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%7D%7Bu%7D)
v = 0.72u
therefore the outgoing kinetic energy = 0.5 x m x ![(0.72u)^{2}](https://tex.z-dn.net/?f=%280.72u%29%5E%7B2%7D)
outgoing kinetic energy = 0.5 x m x ![0.5184 x u^{2}](https://tex.z-dn.net/?f=0.5184%20x%20u%5E%7B2%7D)
outgoing kinetic energy = 0.5184 (0.5 x m x
)
recall that 0.5 x m x
is our incoming kinetic energy, therefore
outgoing kinetic energy = 0.5184 x (incoming kinetic energy)
from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.
The energy lost would be 100 - 51.84 = 48.16 %
Answer:
Right Hand Rule
Explanation:
When a charged particle travels in a magnetic field, it experiences a force whose magnitude is given by:
![F=qvBsin\theta](https://tex.z-dn.net/?f=F%3DqvBsin%5Ctheta)
where
q is the charge of the particle
v is the velocity
B is the magnetic field strength
is the angle between the directions of v and B
The direction of the force can be determined by using the Right Hand Rule, as follows:
- index finger: this should be put in the direction of the velocity
- middle finger: this should be put in the direction of the magnetic field
- thumb: this will give the direction of the force -> however, for a negative charge (as the electron) the direction must be reversed, so it will be opposite.