m = mass of the ice added = ?
M = mass of water = 1.90 kg
= specific heat of the water = 4186 J/(kg ⁰C)
= specific heat of the ice = 2000 J/(kg ⁰C)
= latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg
= initial temperature of ice = 0 ⁰C
= initial temperature of water = 79 ⁰C
T = final equilibrium temperature = 8 ⁰C
using conservation of heat
Heat gained by ice = Heat lost by water
m (T - ) + m = M ( - T)
inserting the values
m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)
m = 1.53 kg
Answer:
Inter Quartile Range
Explanation:
Quartile is a positional statistical average, which divided the data into 4 equal halves.
Q1 (Lower Quartile) has 25% data below it, 75% above it. Q3 (Upper Quartile) has 75% data below it, 25% above it.
Interquartile range is the measure used to calculate how far the lower & upper quartiles are.
All the continents were connected in one large landmass.If you take a map and cut out all the Continent, you can see that they fit together almost perfectly, like a giant puzzle. This idea supports the fact that <span>all the continents were connected in one large landmass.
</span>hope it helped :)
Answer:
7.0 m/s
Explanation:
First of all, we need to find the time it takes for the fish to reach the water below. This can be done by considering the vertical motion of the fish only, which is a free fall motion, so by using the following suvat equation:
where
s = 4.6 m is the vertical displacement of the fish (choosing downward as positive direction)
u = 0 is the initial vertical velocity of the fish
t is the time
is the acceleration of gravity
Solving for t, we find:
Now can consider the horizontal motion of the fish; since there are no forces along this direction, the fish travels at constant horizontal velocity, and so the distance travelled is
Here we have
d = 6.8 m is the horizontal distance travelled by the fish
t = 0.97 s is the time of flight
Solving,
And since the horizontal velocity of the fish is constant, and it is equal to the initial velocity of the pelican, this means that the initial speed of the pelican was 7.0 m/s.
