Find ( f . g) (x) where f(x) = 1/x^2 + 3 and g (x) = sqrt x-2

Mathematics

1 answer:

melamori03 [73]3 years ago

7 0

Answer:

Step-by-step explanation:

( f . g) (x) is the "product" of functions f(x) and g(x):

( f . g) (x) = ------- * √(x - 2)

x^2

or:

√(x - 2)

( f . g) (x) = ------------

x^2

You might be interested in

Last month, he sold 50 chickens and 30 ducks for $550. This month, he sold 44 chickens and 36 ducks for

STALIN [3.7K]

Answer: chicken $8, duck $5

Explanation:

x - the cost of a chicken
y - the cost of a duck

he sold 50 chickens and 30 ducks for $550: 50x + 30y = 550
he sold 44 chickens and 36 ducks for $532: 44x + 36y = 532

50x + 30y = 550 divide by 10
44x + 36y = 550 divide by 4
______________
50x/10 + 30y/10 = 550/10
44x/4 + 36y/4 = 532/4
______________
5x + 3y = 55
Multiply by (-3)
11x + 9y = 133
______________
5x * (-3) + 3y * (-3) = 55 * (-3)
11x + 9y = 133
______________
-15x - 9y = -165
11x + 9y = 133
______________
Sum up:
-4x + 0y = -32
-4x = -32
x = -32/-4
x = 8

Since 5x + 3y = 55 and x = 8, then:
5 * 8 + 3y = 55
40 + 3y = 55
3y = 55 - 40
3y = 15
y = 15/3
y = 5

6 0

3 years ago

Read 2 more answers

Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b

jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .

So; as each place is fitted with either 0 or 1

$\mathbf{|R|= 2^{10}}$

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

$\mathbf{P(E) = \dfrac{|E|}{|R|}}$