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3 years ago

Find ( f . g) (x) where f(x) = 1/x^2 + 3 and g (x) = sqrt x-2

Mathematics

1 answer:

melamori03 [73]3 years ago

7 0

Answer:

Step-by-step explanation:

( f . g) (x) is the "product" of functions f(x) and g(x):

( f . g) (x) = ------- * √(x - 2)

x^2

or:

√(x - 2)

( f . g) (x) = ------------

x^2

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In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD

dmitriy555 [2]

Answer:

The area of parallelogram ABCD is $78.42 \mathrm{in}^{2}$

Explanation:

Given:

AD = 12 in

$m \angle C=46^{\circ}$

$m \angle D B A=72^{\circ}$

To Find:

The area of parallelogram ABCD=?

Solution:

When we construct the parallelogram with the given data, we get a parallelogram formed by 12 cm as one side and an angle with 46 degrees.

The area of the parallelogram can be calculated by $a b * \sin (a n g l e)$

Substituting the value of a=12 we have

$\text { Area of parallelogram }=12 * \text { bsin } 46$

<u>To find the value of b, </u>

We know that area of a triangle can be expressed as,

$\text { Area of triangle }=(A b / 2) \sin (\text {angle})$

So,

$(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72$

Cancelling BD and 2 on both sides we get,

$12 * \sin 46=A B * \sin 72$

$A B=12 * \frac{\sin 46}{\sin 72}$

Therefore,

$b=\frac{12 \sin 46}{\sin 72}$

Substituting the value of b,

$=12 *\left(\frac{12 \sin 46}{\sin 72}\right) * \sin 46$

=78.42

So the area of the parallelogram is $78.42 \mathrm{in}^{2}$

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4 years ago

Read 2 more answers

1. In the picture below, if major arc BC is 258

WINSTONCH [101]

The answer is attached.

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3 years ago

hi there answer both question and I will make you brinliest of the brainliest also PLEEEASE show each and every step of how you

Troyanec [42]

Answer:

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Step-by-step explanation:

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