How do I solve 3/4 =60% over 100

Mathematics

1 answer:

zepelin [54]3 years ago

5 0

3/4 is 75% so the answer is 75% out of 100

Hope that helps!:)

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Find the number z such that the proportion of observations that are less than z in a standard Normal distribution is 0.5414. (b)

Akimi4 [234]

Answer:

Part (a) The value of Z is 0.10396. Part (b) The value of Z is 0.410008.

Step-by-step explanation:

Consider the provided information.

Part (a)

In order to find the number z such that the proportion of observations that are less than z in a standard Normal distribution is 0.5414, simply find 0.5414 in the table and search for the appropriate Z-value.

Now, observing the table it can be concluded that the value of Z is 0.10396.

Part (b)

Consider the number 65.91%

The above number can be written as 0.6591.

Now, find 0.6591 in the table and search for the appropriate Z-value.

By, observing the table it can be concluded that the value of Z is 0.410008.

7 0

3 years ago

Barron's reported that the average number of weeks an individual is unemployed is 17.5 weeks. Assume that for the population of

Olin [163]

Answer:

$P(16.5$

And using the normal standard table or excel we find the probability:

$P(-1.768< Z< 1.768) = P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the avergae number of weeks an individual is unemployed of a population, and for this case we know the distribution for X is given by:

$X \sim N(17.5,4)$