Ask question

Ask question

All categories

3 years ago

8

Find the solution of this system of linear

1 answer:

bezimeni [28]3 years ago

8 0

8x - 19 = 36
8x = 55
x = 55/8 = 6 7/8

-2x + 19 = -66
-2x = -85
2x = 85
x = 42 1/2

You might be interested in

The area of a trapezoid with height z is 20 sq .cm. The length s of the parallel sides are (2z+3) and (6z-1) cm. Find the height

const2013 [10]

Answer:

Area of a trapezoid = ½(a + b)h, where a and b are the lengths of the parallel sides and h is its height.

From your information 20 = ½(2z + 3 + 6z – 1)z = ½(8z + 2)z = z(4z + 1)

Solve 20 = 4z² + z which is 0 = 4z² + z – 20 using the quadratic formula

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP ME I WILL MARK BRAINLYEST

Korvikt [17]

Question 9:

Given the equations

$5x+2y=6;$

$4x-8y=0$

solving the system of the equations

$\begin{bmatrix}5x+2y=6\\ 4x-8y=0\end{bmatrix}$

$\mathrm{Multiply\:}5x+2y=6\mathrm{\:by\:}4\:\mathrm{:}\:\quad \:20x+8y=24$

$\mathrm{Multiply\:}4x-8y=0\mathrm{\:by\:}5\:\mathrm{:}\:\quad \:20x-40y=0$

$\begin{bmatrix}20x+8y=24\\ 20x-40y=0\end{bmatrix}$

$20x-40y=0$

$-$

$\underline{20x+8y=24}$

$-48y=-24$

$\begin{bmatrix}20x+8y=24\\ -48y=-24\end{bmatrix}$

$-48y=-24$

$\frac{-48y}{-48}=\frac{-24}{-48}$

$y=\frac{1}{2}$

$y = 0.5$ ( 0.5 is the result of rounding 0.5 to the nearest 0.01)

$\mathrm{For\:}20x+8y=24\mathrm{\:plug\:in\:}y=\frac{1}{2}$

$20x+8\cdot \frac{1}{2}=24$

$20x+4=24$

$\frac{20x}{20}=\frac{20}{20}$

$x=1.00$ ( 1.00 is the result of rounding 1 to the nearest 0.01 )

So, the solution is:

(x, y) → (1.00, 0.5)

Question 10)

Similarly the question 10 can be solved.

Given the equations

$5x+2y=9;\:4x-3y=44$

solving

$\begin{bmatrix}5x+2y=9\\ 4x-3y=44\end{bmatrix}$

$\mathrm{Multiply\:}5x+2y=9\mathrm{\:by\:}4\:\mathrm{:}\:\quad \:20x+8y=36$

$\mathrm{Multiply\:}4x-3y=44\mathrm{\:by\:}5\:\mathrm{:}\:\quad \:20x-15y=220$

$\begin{bmatrix}20x+8y=36\\ 20x-15y=220\end{bmatrix}$

$20x-15y=220$

$-$

$\underline{20x+8y=36}$

$-23y=184$

$\begin{bmatrix}20x+8y=36\\ -23y=184\end{bmatrix}$

$-23y=184$

$y=-8.00$ ( -8.00 Rounded to the nearest 0.01 or the Hundredths Place )

$\mathrm{For\:}20x+8y=36\mathrm{\:plug\:in\:}y=-8$

$20x+8\left(-8\right)=36$

$20x=100$

$x=5.00$ ( 5.00 Rounded to the nearest 0.01 or the Hundredths Place )

So, the solution is:

(x, y) → (5.00, -8.00)

8 0

3 years ago

3. Solve for x.<br> 3r +11<br> 9x - 14<br> Plss

Studentka2010 [4]

Answer:

x=12

Step-by-step explanation:

use midpoint theorem that said that the small line segment (3x+11) is half of the segment ( 9x -14)

2(3x +11) = 9x -14

6x +22 = 9x -14; distribute

6x -9x = -22-14; subtract 9x and 22 from both sides

-3x = -36; divide both sides by -3

x= 12

4 0

3 years ago

Is the square root of 87 rational of irrational?

fgiga [73]

No its irrational.The answer its irrational.

7 0

3 years ago

The vertices of ABC are A(-2, 2), B(6,2), and CO, 8). The perimeter of ABC?

Alexxx [7]

Answer:

Perimeter = 22.809836694575

Step-by-step explanation:

A(-2, 2) ; B(6,2) ; C(0, 8)

$AB=\sqrt{\left( 6--2\right)^{2} +\left(2-2 \right)^{2} } =\sqrt{64} =8$

$AC=\sqrt{\left( 0--2\right)^{2} +\left(8-2 \right)^{2} } =\sqrt{40} =2\sqrt{10}$

$BC=\sqrt{\left( 0-6\right)^{2} +\left(8-2 \right)^{2} } =\sqrt{72} =6\sqrt{2}$

Then

The perimeter of ΔABC = AB + BC + AC

$=8+6\sqrt{2} +2\sqrt{10}$

= 22.809836694575

3 0

3 years ago