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irina1246 [14]
3 years ago
15

Use the Distributive Property to find 2/5 × 10 2/3

Mathematics
2 answers:
horsena [70]3 years ago
7 0
I got 4.27 cause I got 4.26 repeating
Grace [21]3 years ago
6 0
4.26666667. (Round it)
You might be interested in
Select the correct answer.
Xelga [282]
The answer to this problem is 2
7 0
2 years ago
The value of expression x<br> 2 + 3x<br> 2 − 5n − 2 when x = 2 is
Mumz [18]

2 + 3x

= 5

<h3>X = 5</h3>

Have a Nice day

3 0
2 years ago
Solve. x – 6 = 14 – 8 0 12 20 –12
lana [24]
The answer is 12 because first we have to simplify 14-8 to 6 so it will be
x-6=6
Then add 6 to both sides lastly simplify 6+6 to 12
So x=12
7 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
Type the correct answer in the box.
Pepsi [2]

Answer:

f(g(-64)) = -190

Step-by-step explanation:

The functions are not well written.

Let us assume;

f(x) = x+1

g(x) = 3x+1

f(g(x)) = f(3x+1)

Replace x with 3x+1 in f(x)

f(g(x)) = (3x+1) + 1

f(g(x)) = 3x + 2

f(g(-64)) = 3(-64) + 2

f(g(-64)) = -192+2

f(g(-64)) = -190

<em>Note that the functions are assumed but same method can be employed when calculating composite functions</em>

8 0
2 years ago
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