To find the value take the b and divide it by two. then square it. here your b value is 2 so 2/2 is 1. squared is. 1.
Answer:the expression is 5x - 2
Step-by-step explanation:
The number of customers in a store on the first day is represented by: (6x - 3).
The number of customers on the second day is represented by: (x - 1)
An expression to find how many more customers visited the store on the first day would be the difference between the number of customers that visited the store on the first day and the number of customers that visited the store on the second day. The expression becomes
6x - 3 - (x - 1)
= 6x - 3 - x + 1
= 6x - x - 3 + 1
= 5x - 2
Answer:
Step-by-step explanation:
If the square has an area of 49 ft^2, then the length of one of its sides is
s = √(49 ft^2) = 7 ft, and its perimeter is P = 4(7 ft) = 28 ft.
As for the rectangle: let W and L represent the width and length, respectively. Then W*L = 24 ft^2 is the area. L = W + 2 ft. Therefore,
W(W + 2) = 24, or W^2 + 2W - 24 = 0, or (W +6)(W - 4) = 0. Thus, W = 4 ft.
The perimeter of this rectangle is P = 2W + 2L, or
P = 2(4 ft) + 2(6 ft) = 24 ft.
The square has the larger perimeter: It is 28 ft.
In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
= 800 milligrams
Then
The weight by which the flea is greater than the ant = (800 - 3) milligrams
= 797 milligrams.
So the flea weighs 797 milligrams more than the ant.
Answer:
(-5.77, 6.46)
Step-by-step explanation:
15x + 9y = 45 ----------- i
9x + 8y = 12----------------ii
Multiply equation i by 9 the coefficient of x in equ ii
And equation ii by 15 the coefficient of x in equ I
9 x 15x + 9y = 45 ----------- i
15 x 9x + 8y = 12----------------ii
135x+81y = 405
135x+120y= 180
Subtract equation ii from I
135x-135x+81y-(+120y)= 405-180
-39y=225
y = 225/-39 = -5.77
Insert the value of y in equ i
15x + 9y = 45
15x+9(-5.77) = 45
15x-51.92=45
15x = 45+51.92
15x= 96.92
x = 96.92/15= 6.46
(x,y) = (-5.77, 6.46)
x = 6.92/15
