Coordinate of A are (0,0)
Coordinates of A' are (5,2)
We can find the distance from A to A' using the distance formula:
Thus, rounded to nearest hundredth, AA' is equal to 5.39
Larger triangle’s base length
a^2 + b^2 = c^2
a^2 + 3^2 = 8^2
a^2 = 8^2 - (3^2)
sqrt(a^2) = sqrt(55)
a = sqrt(55)
__________________
Smaller triangle’s base length:
The same formula applies.
a^2 + 3^2 = 5^2
a^2 = 5^2 - (3^2)
sqrt(a^2) = sqrt(16)
a = 4
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The finale!
Add the two side lengths of a, which is sqrt(55) + 4 (exact answer)
or... 11.416 (unrounded to thousandths place)
Good luck to you!
Hello there.
<span>Which numbers are necessary to solve this problem?
Brian goes to the gym 3 times a week. He exercises for 45 minutes each visit. Fifteen of those minutes are spent on weights and the rest are spent on the treadmill.
How much time does Brian spend on the treadmill in 4 weeks?
Answer: </span><span>3 times a week, 45 minutes, 15 minutes, 4 weeks
</span>
Answer:
1096 more water
Step-by-step explanation:
Let;
x = the water used in general
but used 3 times of the original = 3x
3*(548) = 1644 water a day
How much more water =New - original
where:
new = 1644
original= 548
1644 - 548
=1096 more water