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Andru [333]
3 years ago
10

in youngtown , the population reached 4420 people in 1993. In 1998, there were 5600 residents. What was the population in the ye

ar 2000?
Mathematics
1 answer:
Tom [10]3 years ago
5 0
4420 people in 1993
5600 people in 1998

(5600 - 4420) = 1180....so they gained 1180 people in 5 years (from 1993 to 1998)

1180/5 = 236.....thats 236 people per year.

So in 2000.....which is 2 years from 1998, at 236 per yr = 
5600 + 2(236) = 5600 + 472 = 6072 (population in 2000)
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Solve for distributive property <br> -10( x + 9 )
irinina [24]

Answer: -10x - 90

Step-by-step explanation:

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write the equation of the line that is parallel to the line y=-5/3x-2 and goes throught the point (-3,1)
max2010maxim [7]

Answer:

y = (-5/3)x - 4

Explanation:

The equation of a line with slope m that goes through the point (x1, y1) is:

y-y_1=m(x-x_1)_{}

Additionally, two lines are parallel if they have the same slope.

The slope of the line y = (-5/3)x - 2 is (-5/3) because it is the number beside x.

So, the slope of our line is also -5/3.

Therefore, replacing m by -5/3 and (x1, y1) by (-3, 1), we get that the equation of the line is:

\begin{gathered} y-1=-\frac{5}{3}(x-(-3)) \\ y-1=-\frac{5}{3}(x+3) \end{gathered}

Finally, solving for y, we get:

\begin{gathered} y-1=-\frac{5}{3}x-(\frac{5}{3}\cdot3) \\ y-1=-\frac{5}{3}x-5 \\ y=-\frac{5}{3}x-5+1 \\ y=-\frac{5}{3}x-4 \end{gathered}

So, the answer is:

y = (-5/3)x - 4

4 0
1 year ago
If four is added to a half of a<br>number. The result is equal to 2.<br>What is the number?​
scoundrel [369]

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-2

Step-by-step explanation:

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3 0
3 years ago
Angel and Nina are collecting money for the school fundraiser. Their goal is to raise $75 each. Angel has collected $50 and Nina
Stolb23 [73]

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Find the sum of the first 5 terms of the series.<br> 7 - 14 + 28 - 56+...
almond37 [142]

Answer:

<u>The sum of the first 5 terms of the series is 77.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the sum of the first 5 terms of the series:

1st term = 7

2nd term = - 14

3rd term = 28

4th term = - 56

2. Let's solve the sum of the first 5 terms of the series:

Aₙ = Aₙ₋₁ * -2 ; A₁ = 7

A₁ = 7

A₂ = A₁ * -2 = 7 * - 2 = - 14

A₃ = A₂ * - 2 = -14 * - 2 = 28

A₄ = A₃ * - 2 = 28 * - 2 = - 56

A₅ = A₄ * - 2 = -56 * - 2 = 112

Sum of the first 5 terms of the series = 7 - 14 + 28 - 56 + 112

<u>Sum of the first 5 terms of the series = 77</u>

8 0
3 years ago
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