Answer:
The perimeter of triangle ΔABC is approximately;
(A) 20.0
Step-by-step explanation:
In ΔABC, the coordinates of the vertices are given as follows;
A(-4, 1), B(-2, 3), C(3, -4)
The length, 'l', of the sides of the triangle with known 'x', am]nd 'y' coordinates are given as follows;
Therefore, we have;
The length of segment = √((3 - 1)² + (-2 - (-4))²) = 2·√2 ≈ 2.83
The length of segment = √(((-4) - 3)² + (3 - (-2))²) = √74 ≈ 8.6
The length of segment = √(((-4) - 1)² + (3 - (-4))²) = √74 ≈ 8.6
The perimeter of a geometric shape is equal to the sum of the length of sides of the figure
The perimeter of triangle ΔABC = (The length of segment ) + (The length of segment ) + (The length of segment )
∴ The perimeter of triangle ΔABC = 2·√2 + √74 + √74 ≈ 20.0.
It is 252. hope I helped!
Answer:
(6,2)
Step-by-step explanation:
Basically the rectangle has to match one coordinate in the x position and one in the y position.
Since there are already two points in the 2 x position it should take the x position of the third one (6)
Since there are already two points in the 5 y position it should take the y position of the third one (2)
put these together to get your answer of (6,2)
If the length of a side is x, then the surface area of a face of the cube is x squared. there are six sides in a cube so 6(x^2) would be the surface area.
6(x^2)=150
(x^2)=25
x=5
Answer:
427.26 in^2; 628.32 in^2
Step-by-step explanation:
Lateral=surface area-base
Lateral= 628.32-201.06
Lateral= 427.26
Surface area=628.32