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4 years ago

What is the solution to the linear equation? –12 + 3b – 1 = –5 – b

Mathematics

2 answers:

PtichkaEL [24]4 years ago

8 0

Answer:

b=2

Step-by-step explanation:

-12 + 3b -1 = -5 - b

-13 + 3b = -5 - b

+13 = +13

_____________

3b = 8 - b

+b = +b

_________

4b = 8

/4 = /4 <---divide 8 by 4

_______________

b = 2

marysya [2.9K]4 years ago

4 0

-12+3b-1=-5-b
Combine like terms to get:
3b-13=-5-b
Add 13 to both sides:
3b= 8-b
Add b to both sides:
4b=8
Divide both sides by 4:
4b/4=8/4
b=2

Final answer
b=2

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A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

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From the first equation we find that:

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By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

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3 years ago

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Korvikt [17]

Answer:

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Plug in to solve the chart.

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3 years ago

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nydimaria [60]

Answer:

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Step-by-step explanation:

3x-5x+5.6=-14.4

Simplify

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