Answer:
m∠MON = 15°
Step-by-step explanation:
The given parameters are;
m∠LON = 77°
m∠LOM = 9·x + 44°
m∠MON = 6·x + 3°
By angle addition postulate, we have;
m∠LON = m∠LOM + m∠MON
Therefore, by substituting the known values, we have;
∴ 77° = 9·x + 44° + 6·x + 3°
77° = 9·x + 44° + 6·x + 3° = 15·x + 47°
77° = 15·x + 47°
77° - 47° = 15·x
15·x = 77° - 47° = 30°
15·x = 30°
x = 30°/15 = 2°
x = 2°
Given that m∠MON = 6·x + 3° and x = 2°, we have;
m∠MON = 6 × 2° + 3° = 12° + 3° = 15°
m∠MON = 15°.
Answer:
a. yes
b. Q
c. line MP
Step-by-step explanation:
a. "Collinear" means "on the same line". The diagram shows point K on the same line with M and P, so ...
yes, M, P, and K are collinear
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b. N, W, and U are the corners of face NUWQ, so point Q is also in that plane.
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c. The plane MPQ includes face MPQN. The plane TVP includes face TVPM.
Line MP (or PM) is the line where these planes intersect.
Answer:
3/8
Step-by-step explanation:
convert 1/4 to 2/8 and then subtract and that would equal the distance. distance of 3/8 hope this helps
Answer:
6x+4y
Step-by-step explanation:
It's the identity equation so
