Simplify the expression -2(2x+y)-7x+2y

write the equation of the parabola and a vertex form and standard form given the following information

beks73 [17]

Answer:

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

(9)

Here (h, k) = (3, - 2), thus

y = a(x - 3)² - 2

To find a substitute (2, 3) into the equation

3 = a(2 - 3)² - 2 ( add 2 to both sides )

5 = a(- 1)² = a , then

y = 5(x - 3)² - 2 ← in vertex form

y = 5(x² - 6x + 9) - 2

= 5x² - 30x + 45 - 2

y = 5x² - 30x + 43 ← in standard form

(10)

Here (h, k) = (2, - 5), thus

y = a(x - 2)² - 5

To find a substitute (5, 4) into the equation

4 = a(5 - 2)² - 5 ( add 5 to both sides )

9 = a(- 3)² = 9a ( divide both sides by 9 )

a = 1

y = (x - 2)² - 5 ← in vertex form

y = x² - 4x + 4 - 5

y = x² - 4x - 1 ← in standard form

4 0

3 years ago

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Is it (sss) (side side side ) Hypotenuse-Leg (HL), ssa?(sas) aaa,asa,aas?

Reil [10]

Here, both the triangles have equal sides.
So, the two triangles are related by SSS.
If all the sides of a triangle are equal to all the sides of another triangle, so the triangles are congruent to each other.

Answer:

SSS, congruent.

Hope you could get an idea from here.

Doubt clarification - use comment section.

4 0

2 years ago

Which step in the construction of copying a line segment ensures that the new line segment has

Nesterboy [21]

The steps 5 and 6 in the construction of a new line segment ensures the lengths are equal.

A line segment in geometry has two different points on it that define its boundaries. Alternatively, we may define a line segment as a section of a line that joins two points.

Below are the steps for copying a line segment:

1. Let's begin with a line segment we need to copy, AB.

2. we take a point C at this stage. That will be one endpoint of the new line section, either below or above AB.

3. Now we place the the compass pointer on the point A of line segment AB.

4. We spread the compass out until point B, making sure that its breadth corresponds to the length of AB.

5. We place the compass tip on the point C created in step 2 without adjusting the compass's width.

6. We now draw a rough arc without adjusting the compass's settings. we add a point D oh the arc . The new line segment will be formed by this.

7. From C, draw a line to D;CD thus formed is equal to AB.

Hence steps 5 and 6 are the steps in the construction of a new line segment which ensures the lengths are equal.

To learn more about line segment visit:

brainly.com/question/25727583

#SPJ9

5 0

1 year ago

What is 62.465 rounded to the nearest tenth

lukranit [14]

62 because it's 62.465 and The nearest 10th will be 62

5 0

3 years ago

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How many numbers can you make between 0-99 using exactly four 4s?

MAVERICK [17]

Answer:

Number Four Fours Term Solved By

0 4 - 4 + 4 - 4 johnv

1 (4/4) / (4/4) johnv

2 4/4 + 4/4 pilot

3 (4+4+4) / 4 pilot

4 [ (4/4) ^4 ] * 4 catbells

5 [ 4*4 +4 ] / 4 pilot

6 [ (4+4) /4 ] +4 scruffy

7 4+4 - (4/4) Flora Flatbelly

8 4*4 - 4 - 4 catbells

9 4/4 +4 +4 scruffy

10 4 + √4 + √4 + √4 P Rubie

11 44 / (√4 + √4) christina

12 4 + 4 + √4 + √4 johnv

13 4!/(√4) + 4/4 tackline

14 4+4+4 + √4 D12Bit

15 (44/4)+4 D12Bit

16 4*4*4 / 4 D12Bit

17 4*4 + 4/4 D12Bit

18 4*4 + 4 / √4 D12Bit

19 4! - 4 - 4/4 ?

Solutions to the Second Challenge: 20 to 99

Number Four Fours Term Solved By

20 4 * 4 + √4 + √4

21 4! - 4 + 4/4

22 4! - (4! / 4 - 4)

23 4! - 4^(4-4)

24 4 * ( 4 + 4/√4 )

25 4! + 4^(4-4)

26 4! + (4! / 4 + 4)

27 4! + 4 - 4/4

28 4! + 4 * (4/4)

29 4! + 4 + 4/4

30 (4 + 4/4)! / 4

31 (4! + 4)/4 +4! MicheleR

32 4*4 + 4*4

33 (4 - .4)/.4 + 4! IceMantis

34 4*4 * √4 + √

35 4! + 44/4

36 4*4 * √4 + 4

37 4! + (4! + √4) / √4 christina

38 44 - 4 - √4

[39] 4! + 4! - 4/.4~

40 44 - √4 - √

41 (4*4 + .4) / .4

42 44 - 4/√4

43 44 - 4/4

44 44 + 4 - 4

45 44 + 4/4

46 44 + 4/√4

47 4! + 4! - 4/4

48 44 + √4 + √4

49 4! + 4! + 4/4

50 44 + 4! / 4

51 (4! - 4 + .4) / .4 Mr.B

52 44 + 4 + 4

[53] 44 + 4 / .4~

54 4! + 4! + (4! / 4)

55 [4! - ( 4 / √4 ) ] IceMantis

56 44 + 4! / √4

[57] 4! + 4! + 4/.4~

58 4! + 4! + 4/.4 IceMantis

59 4!/.4 - 4/4 FireMantis

60 44 + 4 * 4

61 4!/.4 + 4/4 FireMantis

62 (4 + 4) ^ √4 - √4

63 (4! + √4) / .4 - √4 FireMantis

64 4 * 4 * √4 * √4

65 (4^4 +4) / 4 Jeremy

66 (4 + 4) ^ [√4] + √4

67 [4! + √4] / .4 + √4 FireMantis

68 (4 + 4) ^ √4 + 4

69 (4!+4-.4)/.4 Partick

70 44 + 4! + √4 FireMantis

71 (4 + 4! + .4) / .4 IceMantis

72 [ (4! / 4) ^ √4 ] * √4

[73] [4! * √4 + √.4~)] / √.4~) capOCC

74 4! + 4! + 4! + √4 FireMantis

75 (4! + √4 + 4) / .4 FireMantis

76 4!*4 - 4! + 4 Jeremy

[77] (4/.4~) ^ √4 - 4 FireMantis

78 √4 / .4~) * [4! + √4] ArBeeJay Ruakura

79 (4/.4~) ^ √4 - √4

80 4! * 4 - 4*4 -

[81] (4/.4~) * (4/.4~) -

82 (4! / .4) + 4! - √4 Partick

[83] (4/.4~) ^ √4 + √4 -

84 4! * 4 - 4! / √4 -

[85] (4/.4~) ^ √4 + 4 -

86 4!*4 - 4/.4 IceMantis

87 4! * 4 - 4/.4~ -

88 4! * 4 - 4 - 4 -

89 4! + [4! + √4]/.4 RyVikOCC

90 4! * 4 - 4! / 4 -

91 4 * 4! - (√4 / .4) IceMantis

92 4! * 4 - √4*4) -

[93] 4 * 4! - [ √4 / √(.4~) ] IceMantis

94 4! * 4 - 4/√4 -

95 4! * 4 - 4/4 -

96 4! * 4 + 4 - 4 -

97 4! * 4 + 4/4 -

98 4! * 4 + 4/√4 -

[99] (4!*√4-4) / .4~ IceMantis

Step-by-step explanation:

7 0

3 years ago

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