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3 years ago

Is shelfstone above or below ground

Physics

1 answer:

dexar [7]3 years ago

6 0

It believe it is under the ground because it normally is in tunnels

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two pirate ships are having a battle, ship 1 fires a cannon ball 60 m/s at an angle of 30 degrees at pirate ship 2. If ship 2 is

GREYUIT [131]

Answer:

see to sail another day

Explanation:

4 0

3 years ago

While standing on an open bed of a truck moving at 35 m/s, an archer sees a duck flying directly overhead. The archer shoots an

pashok25 [27]

Answer:

Part a)

$t = 20 s$

Part b)

$x = 700 m$

Part c)

Since horizontal speed of truck and the arrow is same so the arrow will strike at the position of the archer as they both moving with same speed

Explanation:

Part a)

As we know that the arrow moves with uniform acceleration in vertical direction so we can use kinematics in Y direction

Here we know that

$\Delta y = v_y t + \frac{1}{2}at^2$

since the arrow lands at the same height so its vertical displacement of whole motion is zero

so we will have

$0 = 98 t - \frac{1}{2}(9.8) t^2$

$0 = 98 t - 4.9 t^2$

$t = 20 s$

Part b)

Horizontal distance moved by the arrow

$x = v_x t$

here horizontal speed of arrow is same as that of speed of truck

so we will have

$x = 35 \times 20$

$x = 700 m$

Part c)

Since horizontal speed of truck and the arrow is same so the arrow will strike at the position of the archer as they both moving with same speed

6 0

3 years ago

A rectangular wooden block measures 10.0 cm × 4.00 cm × 2.00 cm. When the block is placed in water, it floats horizontally, with

Alex Ar [27]

Answer:

825 kgm⁻³

Explanation:

ρ = density of wood = ?

ρ' = density of water = 1000 kgm⁻³

V = volume of wood = 10 x 4 x 2 = 80 cm³ = 80 x 10⁻⁶ m³

V' = Volume of water displaced = 10 x 4 x 1.65 = 66 cm³ = 66 x 10⁻⁶ m³

Using equilibrium of force in vertical direction

Force of buoyancy = Weight of the wood

ρ' V' g = ρ V g

ρ' V' = ρ V

(1000) (66 x 10⁻⁶) = ρ (80 x 10⁻⁶)

ρ = 825 kgm⁻³

5 0

3 years ago

Starting from rest and moving in a straight line, a cheetah

UNO [17]

The average acceleration of the cheetah is 7.75 m/s²

The given parameters;

velocity of the cheetah, v = 31 m/s

time of motion, t = 4 seconds

The average acceleration of the cheetah is calculated as follows;

$Average \ acceleration = \frac{\Delta velocity}{\Delta time } \\\\Average \ acceleration = \frac{v-u}{t}$

where;

v is the final velocity

u is the initial velocity

t is the time of motion

Assuming the cheetah started from rest, the initial velocity, u = 0

The average acceleration is calculated as follows;

$Average \ acceleration = \frac{v-u}{t} = \frac{31-0}{4} = 7.75 \ m/s^2$

Thus, the average acceleration of the cheetah is 7.75 m/s²

Learn more here: brainly.com/question/17280180

3 0

3 years ago

If a metal ball of mass 45kg is released at a height of 50m with acceleration due to gravity of 1.66m/s^2 then how much time wil

Yuki888 [10]

Answer:

t = 7.76sec

Explanation:

t²=(2s)/a

t²=(2 x 50)/1.66

t²=60.24

t=√60.24

t=7.76sec

3 0

3 years ago