Answer:
Basic kinematics, negating drag and assuming ideal conditions, we use the equation:
d=vi*t+1/2*a*t^2
Since vi is 0 (we know this because you’re dropping it, not throwing it)…
…and the only acceleration acting on it is gravity, a=9.8 m/s^2…
…we get
d=1/2(9.8)(5)^2
Explanation:
Some quick mental math tells us that this is about 125 m.
Plugging it in, we find it to be 122.5 m.
If the Earth's axis were closer to "straight up and down" than
the present 23.5°, then . . .
-- The areas around the north and south poles where the sun
can be up or down for more than 24 hours would be smaller.
-- The "Tropic Zone", between the Tropic of Cancer and the
Tropic of Capricorn, where it's possible for the sun to be
directly overhead, would be narrower.
-- There would be less difference, everywhere, between the
lengths of daylight on the "longest day" and the "shortest day"
of the year.
-- The seasons would be less extreme everywhere. There would
be less difference, everywhere, between the coldest part of the
Winter and the warmest part of the Summer.
Answer:
Kepler's Third Law
T = 2 π r 3 G M E . T = 2 π r 3 G M E . For an ellipse, recall that the semi-major axis is one-half the sum of the perihelion and the aphelion. For a circular orbit, the semi-major axis (a) is the same as the radius for the orbit.
Answer:
<em>The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s</em>
Explanation:
<u>Free Fall Motion
</u>
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is 
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:

Given a grapefruit free falls from a tree and hits the ground t=0.72 s later, we can calculate the height it fell from:

y = 2.54 m
The final speed is computed below:

vf = 7.06 m/s
The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s