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Mama L [17]
3 years ago
15

In a steam turbine,

Physics
1 answer:
Zanzabum3 years ago
8 0

Answer:

Efficiency = 0.273 = 27.3%

Explanation:

The ideal energy that can be produced by certain mass of diesel fuel is given as follows:

E_{ideal} = (HV)(m)

where,

HV = Heating Value of Diesel = 42 - 46 MJ = 44 MJ (Taking average value)

m = mass of diesel fuel = 0.3 kg

E(ideal) = Ideal energy produced by this mass of fuel = ?

Therefore,

E_{ideal} = (44\ MJ/kg)(0.3\ kg)\\E_{ideal} = 13.2\ MJ\\

So, the efficiency can be given as:

Efficiency = \frac{E_{actual}}{E_{ideal}}\\\\Efficiency = \frac{3.6\ MJ}{13.2\ MJ}

<u>Efficiency = 0.273 = 27.3%</u>

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If you drop a rock off a cliff and it hits the ground 3 seconds later how tall is that cliff
skelet666 [1.2K]

Answer:

Basic kinematics, negating drag and assuming ideal conditions, we use the equation:

d=vi*t+1/2*a*t^2

Since vi is 0 (we know this because you’re dropping it, not throwing it)…

…and the only acceleration acting on it is gravity, a=9.8 m/s^2…

…we get

d=1/2(9.8)(5)^2

Explanation:

Some quick mental math tells us that this is about 125 m.

Plugging it in, we find it to be 122.5 m.

6 0
3 years ago
A very small tilt in Earth’s axis would likely cause ____.
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3 0
4 years ago
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Kepler's 3 laws with formula centerpital<br> forces
madreJ [45]

Answer:

Kepler's Third Law

T = 2 π r 3 G M E . T = 2 π r 3 G M E . For an ellipse, recall that the semi-major axis is one-half the sum of the perihelion and the aphelion. For a circular orbit, the semi-major axis (a) is the same as the radius for the orbit.

6 0
3 years ago
A grapefruit falls from a tree and hits the ground 0.72 s later.
xxTIMURxx [149]

Answer:

<em>The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s</em>

Explanation:

<u>Free Fall Motion </u>

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2.

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The distance traveled by a dropped object is:

\displaystyle y=\frac{gt^2}{2}

Given a grapefruit free falls from a tree and hits the ground t=0.72 s later, we can calculate the height it fell from:

\displaystyle y=\frac{9.8\cdot 0.72^2}{2}

y = 2.54 m

The final speed is computed below:

vf=9.8\cdot 0.72

vf = 7.06 m/s

The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s

6 0
3 years ago
Which one i need help
Lostsunrise [7]

Answer:

C

Explanation:

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