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3 years ago

In a steam turbine,

Physics

1 answer:

Zanzabum3 years ago

8 0

Answer:

Efficiency = 0.273 = 27.3%

Explanation:

The ideal energy that can be produced by certain mass of diesel fuel is given as follows:

$E_{ideal} = (HV)(m)$

where,

HV = Heating Value of Diesel = 42 - 46 MJ = 44 MJ (Taking average value)

m = mass of diesel fuel = 0.3 kg

E(ideal) = Ideal energy produced by this mass of fuel = ?

Therefore,

$E_{ideal} = (44\ MJ/kg)(0.3\ kg)\\E_{ideal} = 13.2\ MJ\\$

So, the efficiency can be given as:

$Efficiency = \frac{E_{actual}}{E_{ideal}}\\\\Efficiency = \frac{3.6\ MJ}{13.2\ MJ}$

<u>Efficiency = 0.273 = 27.3%</u>

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Answer:

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3 years ago

To leave the gravitational pull of the Earth, and explore other planets, satellites must have at least:

Alexxx [7]

Answer:

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Explanation:

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3 years ago

The induced magnetic field at radial distance 4.0 mm from the central axis of a circular parallel-plate capacitor is 1.8 ✕ 10−7

wel

Answer:

$\frac{dE}{dt}=2.07*10^{13}\frac{V/m}{s}$

Explanation:

According to Gauss's law, the electric flux through the circular plates is defined as the electric field multiplied by its area:

$\Phi=EA=E(\pi R^2)(1)$

The magnetic field around the varying electric field of the circular plates is given by:

$B=\frac{\epsilon_0 \mu_o}{2\pi r}\frac{d\Phi}{dt}(2)$

Replacing (1) in (2) and solving for $\frac{dE}{dt}$ :

$B=\frac{\epsilon_0 \mu_o\pi R^2}{2\pi r}\frac{dE}{dt}\\\frac{dE}{dt}=\frac{2rB}{\epsilon_0 \mu_o R^2}\\\frac{dE}{dt}=\frac{2(4*10^{-3}m)(1.8*10^{-7}T)}{(8.85*10^{-12}\frac{C^2}{N\cdot m^2})(4\pi *10{-7}\frac{Tm}{A})(2.5*10^{-3}m)^2}\\\\\frac{dE}{dt}=2.07*10^{13}\frac{V/m}{s}$