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3 years ago

15

In a steam turbine,

1 answer:

Zanzabum3 years ago

8 0

Answer:

Efficiency = 0.273 = 27.3%

Explanation:

The ideal energy that can be produced by certain mass of diesel fuel is given as follows:

$E_{ideal} = (HV)(m)$

where,

HV = Heating Value of Diesel = 42 - 46 MJ = 44 MJ (Taking average value)

m = mass of diesel fuel = 0.3 kg

E(ideal) = Ideal energy produced by this mass of fuel = ?

Therefore,

$E_{ideal} = (44\ MJ/kg)(0.3\ kg)\\E_{ideal} = 13.2\ MJ\\$

So, the efficiency can be given as:

$Efficiency = \frac{E_{actual}}{E_{ideal}}\\\\Efficiency = \frac{3.6\ MJ}{13.2\ MJ}$

<u>Efficiency = 0.273 = 27.3%</u>

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What type of spectrum is emitted by a low-density luminous cloud of hot gases?

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Does the mass of a pendulum affects the period of oscillation

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3 years ago

A 25 N force stretches a spring 280 cm. What was the spring constant?

boyakko [2]

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4 0

3 years ago

Read 2 more answers

Water ice has a density of 0.91 g/cm2, so it will float in liquid water. Imagine you have a cube of ice, 10 cm on a side. a. Wha

Reptile [31]

Answer:

(i) W = 8.918 N

(ii) $V = 9.1 \times 10^{-4} m^3$

(iii) d = 9.1 cm

Explanation:

Part a)

As we know that weight of cube is given as

$W = mg$

$W = \rho V g$

here we know that

$\rho = 0.91 g/cm^3$

$Volume = L^3$

$Volume = 10^3 = 1000 cm^3$

now the mass of the ice cube is given as

$m = 0.91 \times 1000 = 910 g$

now weight is given as

$W = 0.910 \times 9.8 = 8.918 N$

Part b)

Weight of the liquid displaced must be equal to weight of the ice cube

Because as we know that force of buoyancy = weight of the of the liquid displaced

$W_{displaced} = 8.918 N$

So here volume displaced is given as

$\rho_{water}Vg = 8.918$

$1000(V)9.8 = 8.918$

$V = 9.1 \times 10^{-4} m^3$

Part c)

Let the cube is submerged by distance "d" inside water

So here displaced water weight is given as

$W = \rho_{water} (L^2 d) g$

$8.918 = 1000(0.10^2 \times d) 9.8$

$d = 0.091 m$

so it is submerged by d = 9.1 cm inside water

4 0

4 years ago

A hill is 132 m long and makes an angle of 12.0 degrees with the horizontal. As a 54 kg jogger runs up the hill, how much work d

TEA [102]

Answer:

14523.55J

Explanation:

The work done by the jogger against gravity is given by the following equation;

$W=mgh.................(1)$

where m is the mass, g is acceleration due to gravity taken as $9.8m/s^2$ and h is the height of the hill.

Since the length of the hill is 132m and it is inclined at 12 degrees to the horizontal, the height is thus given as follows;

$h=132sin12^o\\h=27.44m$

Substituting this into equation (1) with all other necessary parameters, we obtain the following;

$W=54*9.8*27.44\\W=14523.55J$

4 0

3 years ago