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Tanzania [10]
4 years ago
8

When the particles in a medium vibrate perpendicular to the direction the wave is traveling, this type of waves is called a:

Physics
1 answer:
bija089 [108]4 years ago
3 0
This kind of wave is called a transverse wave. 
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A 20 kg bicycle carrying a 50 kg
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Where's the question?

The weight of the bicycle will be 70kg which means that the bicycle has more friction to the ground.

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3 years ago
What happen to tbe brightness when one of the bulb removed from patallel circiut​
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The current decreases as the overall resistance increases. In addition, if one bulb is removed from the “chain” the other bulbs go out. ... If light bulbs are connected in parallel to a voltage source, the brightness of the individual bulbs remains more-or-less constant as more and more bulbs are added to the “ladder”.
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3 years ago
You wish to lift a 12,000 lb stone by a vertical distance of 15 ft. Unfortunately, you can only generate a maximum pushing force
DochEvi [55]

Answer:

5,760,000 lb-ft²/s²

Explanation:

Work done, W = mgy where m = mass of stone = 12,000 lb, g = 32 ft/s² and y = vertical distance = 15 ft.

So, W = mgy = 12,000 lb × 32 ft/s² × 15 ft. = 5,760,000 lb-ft²/s²

6 0
3 years ago
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slavikrds [6]
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6 0
3 years ago
if charge is located at center of spherical volume and electric flux through surface of sphere is Φ what would be flux through s
jonny [76]

Answer:

The flux will be nine times as great.

Explanation:

The electric flux due to a charge Q located in the center of a sphere can be obtained using Gauss's law. Considering a Gaussian surface in the form of a sphere of radius r:

\Phi_E=\int\limits {Ecos\theta dS} \,

The electric field (E) is parallel to the surface vector (dS), so \theta=0

\Phi_E=\int\limits{Ecos(0)dS} \,\\\Phi_E=E\int\limits{dS} \,\\\Phi_E=ES\\\Phi_E=E4\pi r^2

Since the electric flux is proportional to the square of the sphere's radius,  if radius of sphere were tripled, the flux will be nine times as great.

7 0
3 years ago
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