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tensa zangetsu [6.8K]
3 years ago
6

If 333 + 555 = 999 And 123 + 456 = 488 And 505 + 213 = 809 Then 344 + 732 = ???

Mathematics
2 answers:
erastova [34]3 years ago
6 0
The answer is: 344 + 732 = 1076
Len [333]3 years ago
5 0

Answer:

1076

Step-by-step explanation:

I just need points lol

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What is the sum of (q+r)-(r+10)
KATRIN_1 [288]

Answer:

q+10 is the answer

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3 years ago
In Inglis County me were 2,277 student athletes competing in spring sports in 2014. Thai was of the number which was of the numb
Anna35 [415]
2014⇒2277 athletes

2013⇒2070 athletes.
x=number of athletes in 2013
110% of x=2277
(110/100x=2277
x=(2277*100)/110=2070

2012⇒2300 athletes. 
x=number of athletes in 2012
90% of x=2070
(90/100)x=2070
x=(2070*100)/90=2300

Answer: 2300 athletes were signed up for a spring sport in 2012. 
7 0
4 years ago
Factor the quadratic expression completely<br> 6x^2 – 28x + 32
Fiesta28 [93]
Answer: 2(x-2)(3x-8)

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3 years ago
Two distinct solid fuel propellants, type A and type B, are being considered for a space program activity. Burning rates of the
Finger [1]

Answer:

C.I. =  (2.297, 11.703)

Step-by-step explanation:

The t-statistic for difference of mean is given by,

t=\frac{\bar{x_{1}}-\bar{x_{2}}}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}}

Here, \bar{x_{1}} = 84

\bar{x_{2}} = 7

s₁ = 4

n₁ = 12

s₂ = 6

n₂ = 18

Substituting all value in formula,

We get, t = -3.541 at 28 degree of freedom.

Using this formula, we get, t = 1.5342

Therefore, based on the data provided, the 99% confidence interval for the difference between the population means \bar{x_{1}}-\bar{x_{2}} is: 2.297 < \bar{x_{1}}-\bar{x_{2}} < 11.703

which indicates that we are 99% confident that the true difference between population means is contained by the interval (2.297, 11.703)

6 0
3 years ago
Solve the equation |x-2|-3=0 first by finding the zeros of<br> y=|x-2|-3 and then algebraically.
tino4ka555 [31]

Answer:

The solution of given equation are -1 and 5.

Step-by-step explanation:

The given equation is

|x-2|-3=0

We need to solve the above equation by finding the zeros of

y=|x-2|-3

The vertex form of an absolute function is

y=a|x-h|+k

where, a is constant and (h,k) is vertex.

Here, h=2, k=-3. So vertex of the function is (2,-3).

The table of values is

   x           y

   0         -1

   2         -3

   4         -1

Plot these points on a coordinate plane and draw a V-shaped curve with vertex at (2,-3).

From the given graph it is clear that the graph intersect x-axis at -1 and 5. So, zeroes of the function y=|x-2|-3 are -1 and 5.

Therefore the solution of given equation are -1 and 5.

Now solve the given equation algebraically.

|x-2|-3=0

Add 3 on both sides.

|x-2|=3

x-2=\pm 3

Add 2 on both sides.

x=\pm 3+2

x=3+2 and x=-3+2

x=5 and x=-1

Therefore the solution of given equation are -1 and 5.

3 0
4 years ago
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