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MaRussiya [10]
3 years ago
9

Can someone please help me

Mathematics
1 answer:
nydimaria [60]3 years ago
6 0
You answer is correct
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Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)
Wittaler [7]

(tanθ + cotθ)² = sec²θ + csc²θ

<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ

<u>Evaluate middle term</u>: 2tanθcotθ = 2*\frac{sin\theta}{cos\theta}*\frac{cos\theta}{sin\theta} = 2

⇒ tan²θ + 2+ cot²θ

= tan²θ + 1 + 1 + cot²θ

<u>Apply trig identity:</u>  tan²θ + 1 = sec²θ

⇒ sec²θ + 1 + cot²θ

<u>Apply trig identity:</u>  1 + cot²θ = csc²θ

⇒ sec²θ + csc²θ

Left side equals Right side so equation is verified


7 0
3 years ago
Find the midpoint of JK if J(-7. -5) and K(-3,7).
qaws [65]

Answer:

( − 5 , 1 )

Step-by-step explanation:

Use the midpoint formula to find the midpoint of the line segment.

7 0
3 years ago
What is the Slope of the line that passes through points (4, -2) and (3, 1)?
Sedbober [7]

Answer:

-3

Step-by-step explanation:

slope formula is y2-y1 over x2-x1

if we plug in the values and solve, that gets you -3.

6 0
2 years ago
Read 2 more answers
Which expressions are equivalent to √/32?<br> 4√8<br> 08<br> 2√8<br> 4√2<br> 16<br> 16√2
vaieri [72.5K]

Answer: 4√2

square root of a number is the factor that we can multiply by itself to get that number.

The square root symbol is also called as a RADICAL.

Perfect squares are the squares of the integers also called as square numbers.

to find the square root of non-perfect squared numbers we have to check the number with a near-perfect squared numbers

how to find square root of non perfect squared numbers:

If we can't figure out what factor multiplied by itself will result in the given number, we can make a factor tree.

Factor tree of 32 = 2*2*2*2*2

                            = (2*2) * (2*2) *2

                            = (4)2 *2

Therefore √/32 = √/2*2*2*2*2

                          = √/(4)2*2

                          = 4√/2

learn more about square roots here:

brainly.com/question/428672

brainly.com/question/3617398

#SPJ9

8 0
1 year ago
Find the equation of the straight line that passes through the points (1, 10) and (3, 2)
slava [35]

Answer:

y = -4x+14

Step-by-step explanation:

First find the slope

m = (y2-y1)/(x2-x1)

m = (2-10)/(3-1)

  =-8/2

  = -4

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -4x+b

Substitute a point into the equation

10 = -4(1)+b

Add 4 to each side

14 = b

y = -4x+14

8 0
2 years ago
Read 2 more answers
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