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Alinara [238K]
3 years ago
9

G= 2/3ns solve for variable "s"

Mathematics
1 answer:
Kisachek [45]3 years ago
6 0
“S” = 3g /2n
I would think
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Coffee beans worth $ 10.50 $10.50 per pound are to be mixed with coffee beans worth $ 13.00 $13.00 per pound to make 50 50 pound
MAVERICK [17]

Answer: 30 pounds of coffee beans worth $10.50 per pound was used.

20 pounds of coffee beans worth $13.00 per pound was used.

Step-by-step explanation:

Let x represent the number of coffee beans worth $10.50 per pound that should be mixed.

Let y represent the number of coffee beans worth $13.00 per pound that should be mixed.

50 pounds of beans worth $11.50 per pound is to be made. The total cost of the mixture would be

50 × 11.5 = 575

This means that

10.5x + 13y = 575 - - - - - - - 1

The total number of pounds of each type of coffee used is 50. This means that

x + y = 50

Substituting x = 50 - y into equation 1, it becomes.

10.5(50 - y) + 13y = 575

525 - 10.5y + 13y = 575

- 10.5y + 13y = 575 - 525

2.5y = 50

y = 50/2.5 = 20

x = 50 - 20= 30

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4 years ago
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kolbaska11 [484]

Answer:

p=2

Step-by-step explanation:

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4 years ago
In the bin there is a 45% chance of randomly selecting ripe avocados. If you are picking avocados from the bin, you keep inspect
Archy [21]

Answer:

0.6125

Step-by-step explanation:

We have,

P(ripe avocados) = 0.45 , n = 5

by binomial distribution,

P(x=k) = ${\overset{n}C}_k P^k(1-P)^{n-k}$

P(2 ≤ x ≤ 3) = P(x=2) + P(x=3)

P(x=2) = ${\overset{5}C}_2(0.45)^2(0.55)^3$

           = 10 x (0.45)² x (0.55)³

           = 0.3369

P(x=3) = ${\overset{5}C}_3(0.45)^3(0.55)^2$

           = 10 x (0.45)³ x (0.55)²

           = 0.2756

So, P(2 ≤ x ≤ 3 ) = 0.3369 + 0.2756

                          = 0.6125

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4 years ago
The distance between point A and point B is 2 1/2 units. Which number could represent point B?
zloy xaker [14]
C. 2.0
I just took the test
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3 years ago
Consider the following figure... True or False.. ​
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