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Answer:
26
Step-by-step explanation:
Given that:
At time, t=0, Billy puts 625 into an account paying 6% simple interest
At the end of year 2, George puts 400 into an account paying interest at a force of interest, 1/(6+t), for all t ≥ 2.
If both accounts continue to earn interest indefinitely at the levels given above, the amounts in both accounts will be equal at the end of year n. Calculate n.
In order to calculate n;
Let K constant to be the value of time for both accounts
At time, t=0, the value of time K when Billy puts 625 into an account paying 6% simple interest is:
At year end 2; George amount of 400 will grow at a force interest, then the value of
Therefore:
If K = K
Then:
625 + 37.5 = 300 +50 K
625-300 = 50 K - 37.5 K
325 = 12.5K
K = 325/12.5
K = 26
the amounts in both accounts at the end of year n = K = 26
First find the secant line. The slope of the secant line through
(when
) and
(when
) is the average rate of change of
over the interval
:
The tangent line to
will have a slope determined by the derivative:
Both the secant and tangent will have the same slope when
, or when
.
Answer:
a)8
b)7
c)26
d)60
Step-by-step explanation:
The Venn Diagram is attached
For number of people who saw a single movie only
See the number associated with the movie name excluding all intersection parts
For people who watched only 2 movies exactly
Sum all the intersection parts of any 2 circle parts=6+12+8=26
For total number of students surveyed
Sum up every number in the Venn diagram including the number 5 outside 3 circles(it represents that 5 people did not watch any of the films)
=7+12+10+6+4+8+8+5=60
15.5 (Just round 15.49 to the nearest tenth)