What is the vertex of the quadratic function f(x)=(x-6)(x+2)?
1 answer:
Answer:
(2, -16).
Step-by-step explanation:
(x - 6)(x + 2)
Convert to vertex form:
Expanding the parentheses we have:
x^2 + 2x - 6x - 12
= x^2 - 4x - 12
Completing the square:
= (x - 2)^2 - 4 - 12
= (x - 2)^2 - 16
So the vertex is (2, -16),
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