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3 years ago

What is the vertex of the quadratic function f(x)=(x-6)(x+2)?

Mathematics

1 answer:

Nata [24]3 years ago

4 0

Answer:

(2, -16).

Step-by-step explanation:

(x - 6)(x + 2)

Convert to vertex form:

Expanding the parentheses we have:

x^2 + 2x - 6x - 12

= x^2 - 4x - 12

Completing the square:

= (x - 2)^2 - 4 - 12

= (x - 2)^2 - 16

So the vertex is (2, -16),

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One leg of a right triangle is five and it's hypotenuse is 10. What is the size of its smallest angle?

galina1969 [7]

I hope this helps you

30 degree = k

60 degree = k square root of 3

90 degree = 2k

hypothenus =10 =>90 degree

one leg = 5 => 30 degree

4 0

3 years ago

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nlexa [21]

Answer:

From my understanding i think it is 315, but I think I'm wrong.

Step-by-step explanation:

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2 years ago

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I thought of a number, I added 1 3 4 to it, then I multiplied the result by 2 2 11 and I got 8. What was my number?

Valentin [98]

Given:

In a number, adding $1\dfrac{3}{4}$ , then multiplying the result by $2\dfrac{2}{11}$ we get 8.

To find:

The unknown number.

Solution:

Let the unknown number be x.

According to the question,

$(x+1\dfrac{3}{4})\times 2\dfrac{2}{11}=8$

$(x+\dfrac{1\times 4+3}{4})\times \dfrac{2\times 11+2}{11}=8$

$(x+\dfrac{4+3}{4})\times \dfrac{22+2}{11}=8$

$(x+\dfrac{7}{4})\times \dfrac{24}{11}=8$

Multiply both sides by $\dfrac{11}{24}$ .

$x+\dfrac{7}{4}=8\times \dfrac{11}{24}$

$x+\dfrac{7}{4}=\dfrac{11}{3}$

Subtract $\dfrac{7}{4}$ from both sides.

$x=\dfrac{11}{3}-\dfrac{7}{4}$

$x=\dfrac{44-21}{12}$

$x=\dfrac{23}{12}$

$x=1\dfrac{11}{12}$

Therefore, the required number is $1\dfrac{11}{12}$ .

3 0

2 years ago

You do parenthesis first right? And then do division?

IrinaK [193]

Yes. Parenthesis first, then if any exponents, then multiplication or division, then addition and subtraction. PEMDAS.

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3 years ago

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Please help asap, i will mark as brainliest. please try to find the answer! asap

Hitman42 [59]

1. 14.4 km, 2. 25.2 km, 3. 37.8 km

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2 years ago