Answer: (C) 0.1591
Step-by-step explanation:
Given : A manufacturer of radial tires for automobiles has extensive data to support the fact that the lifetime of their tires follows a normal distribution with


Let x be the random variable that represents the lifetime of the tires .
z-score : 
For x= 44,500 miles

For x= 48,000 miles

Using the standard normal distribution table , we have
The p-value : 

Hence, the probability that a randomly selected tire will have a lifetime of between 44,500 miles and 48,000 miles = 0.1591
Answer:
25.5
Step-by-step explanation:
(150 miles/week) x (1 gallon / 25 miles) x (3 $/gallon)
= (150 x 1 x 3) / (25) (miles-gallon-$ / week-miles-gallon)
= 18 $/week .