I believe it would be done like this:
subtract 2x-8 from both sides. then use cubric formula.
answer should be x= 1.688242
A=1/2bh
b=8+h
A=384
384=1/2(bh)
times 2
768=bh
sub
768=b(8+b)
768=8b+b^2
minus 768 both sides
0=b^2+8b-768
factor
0=(b-24)(b+32)
set to zero
b-24=0
b=24
b+32=0
minus 32
b=-32
false, legnths cannot be negative
b=24
24=8+h
minus 8
16=h
base=24ft
altetude=16ft
So we have -23 degrees to start
Then add 5 to it
It becomes -23+5=-18
Now subtract 7 from that so -18-7=-25 degrees
Hope this helps
False, you graph an open circle on -3 and shade to the right because x must be larger than -3 and it can not equal -3
Part 1) <span>Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?
step 1
find the slope m
m=(y2-y1)/(x2-x1)----></span>m=(25-7)/(30+24)----> m=18/54----> m=1/3
step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15
the answer Part 1) isy=(1/3)*x+15Part 2) <span>Is (51, 33) also on the same line?
</span>if the point (51.33) is on the line
y=(1/3)*x+15then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33
so
<span>the point does not belong to the given line
</span>
the answer Part 2) isthe point does not belong to the given line
see the attached figure