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kari74 [83]
2 years ago
8

3. Choose the equation of the line parallel to the line 5 = -10x - 5y that passes through the point (-2,5). A y=-2x + 1 C y=x-5

By=-12x + 5 D y = 5x + 11​
Mathematics
1 answer:
storchak [24]2 years ago
5 0

Answer:

y = -2x + 1

Step-by-step explanation:

The equation is in standard form, first, we need to convert it to slope-intercept form.

5 = -10x - 5y

5 + 10x = -5y

Divide both sides by -5 to isolate y variable.

y = -2x - 1

If the line is parallel, the slope remains the same.

To find the y-intercept, you need to plug the values of x and y into the equation, which is y = 2x + b

5 = -2(-2) + b

5 = 4 + b

1 = b

The equation is -2x + 1

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How do you solve the following equation: 5-(2x-3)=-8+2x
kirza4 [7]
I believe it would be done like this:
subtract 2x-8 from both sides. then use cubric formula.
answer should be  x= 1.688242

4 0
3 years ago
the area of a triangle is 384 square feet. If its base is 8 feet longer than its altitude, find the length of the base and the a
REY [17]
A=1/2bh
b=8+h
A=384

384=1/2(bh)
times 2
768=bh
sub
768=b(8+b)
768=8b+b^2
minus 768 both sides
0=b^2+8b-768
factor
0=(b-24)(b+32)
set to zero
b-24=0
b=24

b+32=0
minus 32
b=-32
false, legnths cannot be negative

b=24
24=8+h
minus 8
16=h

base=24ft
altetude=16ft
6 0
3 years ago
the temperature in winter night was -23 degrees Fahrenheit the temperature Rose by 5° when the sun rose when the sunset again th
expeople1 [14]

So we have -23 degrees to start

Then add 5 to it

It becomes -23+5=-18

Now subtract 7 from that so -18-7=-25 degrees

Hope this helps

8 0
3 years ago
To graph the inequality x > -3, draw an open circle on -3 and shade to the left.
dedylja [7]
False, you graph an open circle on -3 and shade to the right because x must be larger than -3 and it can not equal -3
8 0
2 years ago
given the two points (-24,7) and (30,25) a. What is an equation passing through the points? b. Is (51, 33) also on the same line
kicyunya [14]
Part 1) <span>Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?

step 1
find the slope m
m=(y2-y1)/(x2-x1)----></span>m=(25-7)/(30+24)----> m=18/54----> m=1/3

step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15

the answer Part 1) is
y=(1/3)*x+15

Part 2) <span>Is (51, 33) also on the same line?
</span>if the point (51.33) is on the line y=(1/3)*x+15
then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33 
so
<span>the point does not belong to the given line
</span>
the answer Part 2) is
the point does not belong to the given line

see the attached figure

7 0
3 years ago
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