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schepotkina [342]
3 years ago
13

What is the distance required for a car traveling at 70 m/s and decelerating at 10 m/s^2 to stop?​

Physics
2 answers:
Zinaida [17]3 years ago
6 0

Answer:

The answer to your question is: 245 m

Explanation:

data

vo = 70 m/s

vf = 0 m/s

a = 10 m/s²

d = ?

Formula

vf² = vo² + 2ad

d = (vf² - vo²) / 2a

Process

d = (0² - 70²) / 2(10)        substitution

d= 4900 / 20                  simplify

d = 245 m

Andre45 [30]3 years ago
3 0

Answer: 245 m

Explanation: V^2 = Vo^2 + 2.a.d

When the car stops, V = 0.

Therefore, 0^2 = 70^2 + 2. (-10).d

0 = 4900 - 20d

d = 4900/20 = 245m

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ExtremeBDS [4]

Answer:

When the resistances are connected in the parallel the equivalent resistance will be always less than the value of the lowest resistance in the parallel circuit.

The equivalent resistance in the parallel circuit can be calculated using the following formula.

1/R=1/R1+1/R2+1/R3

1/R= 1/10+1/20+1/30

1/R=(6+3+2)/60

1/R=11/60

R=60/11

R=5.45 Ohms

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3 years ago
What is the difference between organic and inorganic material?
babymother [125]

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3 years ago
Give two examples of Newton's second law of motion
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3 years ago
Read 2 more answers
Find the wavelength of the balmer series spectral line corresponding to n = 15.
Anna71 [15]

Answer:

371.2 mm

Explanation:

The Balmer series of spectral lines is obtained from the formula

1/λ = R(1/2² -1/n²) where λ = wavelength, R = Rydberg's constant = 1.097 × 10⁷ m⁻¹

when n = 15

1/λ = 1.097 × 10⁷ m⁻¹(1/2² -1/15²)

    = 1.097 × 10⁷ m⁻¹(1/4 -1/225)

    = 1.097 × 10⁷ m⁻¹(0.25 - 0.0044)

    = 1.097 × 10⁷ m⁻¹ 0.245556

    = 2.693 10⁶ m⁻¹

So,

λ  = 1/2.693 10⁶ m⁻¹

    = 0.3712 10⁻⁶ m

    = 371.2 mm

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