Mitosis- Identical daughter cells
Meiosis- not identical
I would say the last one but I’m not sure if I’m directly correct ..
Answer:
Reverses its direction of travel precisely as it reaches the eggs
Explanation:
At the top of the motion: The spring is stretched the least, so, the potential energy of the spring is at a minimum. The mass is lifted as high as it will go, so, the potential energy due to gravity is at a maximum.
When the spring is now at the maximum, now, the maximum potential at the maximum height is
Equal to the energy stored in spring
And the energy stored in spring.
The net force on the object can be described by Hooke’s law, and so the object undergoes simple harmonic motion. Note that the initial position has the vertical displacement at its maximum value X; v is initially zero and then negative as the object moves down; and the initial acceleration is negative, back toward the equilibrium position and becomes zero at that point.
So this apply to the body given, when it get to the egg and it is released the weight will move upward 1m above the equilibrium point and it will return downward 1m below the equilibrium point, that is reverses its direction of travel precisely as it reaches the eggs.
Answer:
ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)
Explanation:
The potential difference while moving from point A to Point B is given as follows:
where,
ΔV = potential difference from A to B = ?
= Potential at point A = 
= Potential at point B = 
Therefore,
where,
k = Colomb's Constant = 9 x 10⁹ N.m²/C²
q = magnitude of charge = 4.88 x 10⁻⁸ C
= distance of point A from charge = 1.36 m
= distance of point B from charge = 0.538 m
Therefore,
<u>ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)</u>
