Question

A proton is on the x axis at x = 1.2 nm . An electron is on the y axis at y = 0.80 nm . Part A Find the net force the two exert on a helium nucleus (charge +2e) at the origin.

Answer 1

Answer:

The net force on the helium nucleus at the origin is equal to $78.79\times 10^{-11}$

Explanation:

Here let the force exerted by the proton be $F_{1}$ and force exerted by electron be $F_{2}$.

⇒The net force becomes $\sqrt{F1^{2}+F2^{2} }$

Now lets calculate $F_{1}$ and $F_{2}$

F = $\frac{KQq}{r^{2} }$ ; where for $F_{1}$ r=$1.2nm$ and for $F_{2}$ r=$O.8nm$

 upon calculating we get $F_{1}$=$32\times 10^{-11}$ and $F_{2}$=$72\times 10^{-11}$

⇒F = $78.79\times 10^{-11}$