The table below shows some physical properties of two unknown samples. Physical Properties Sample Mass Solubility (in water) C 2
2 answers:
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Answer:
Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.
Explanation:
Volume of NaOH = 1.7 ml = 0.0017 L
Molarity of NaOH = 0.0811 M
Moles of NaOH = n
n = 0.0001378 mol
According to reaction, 2 mol of NaOH neutralize 1 mol of sulfuric acid.
Then 0.0001378 mol of NaOH will neutralize:
of sulfuric acid.
Concentration of sulfuric acid in the acid rain sample: x
Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.
<u>Answer:</u> The limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For magnesium:</u>
Given mass of magnesium = 41.0 g
Molar mass of magnesium = 24 g/mol
Putting values in equation 1, we get:
- <u>For iron(III) chloride:</u>
Given mass of iron(III) chloride = 175.0 g
Molar mass of iron(III) chloride = 162.2 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of magnesium and iron(III) chloride follows:
By Stoichiometry of the reaction:
3 moles of magnesium reacts with 2 moles of iron(III) chloride
So, 1.708 moles of magnesium will react with = of iron(III) chloride
As, given amount of iron(III) chloride is more than the required amount. So, it is considered as an excess reagent.
Thus, magnesium is considered as a limiting reagent because it limits the formation of product.
Moles of excess reactant left (iron(III) chloride) = [1.708 - 1.114] = 0.594 moles
Now, calculating the mass of iron(III) chloride from equation 1, we get:
Molar mass of iron(III) chloride = 162.2 g/mol
Moles of iron(III) chloride = 0.594 moles
Putting values in equation 1, we get:
Hence, the limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.