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Kaylis [27]
3 years ago
8

In which situation is the speed of the car constant while its velocity is changing?

Chemistry
1 answer:
Dima020 [189]3 years ago
3 0
When you change direction while maintaining the same speed, you'll change the velocity. 
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A student observes the combustion (burning) of propane (C3H8). Because of the heat and light it generates, the student concludes
insens350 [35]

Answer:

The student's conclusion is not correct

Explanation:

Activation energy is the minimum amount of energy required for a reaction to occur. All reactions require there activation energy to be met before the reaction can proceed. When the temperature of a reaction is increased, the kinetic energy of the reactant molecules increases; colliding more with each other, which makes them "surmount" the activation energy of the reaction faster as compared to a lower temperature.

In combustion, there is burning of an hydrocarbon (in this case propane) in excess oxygen. The burning assists in increasing the kinetic energy of the reactant particles which in turn easily surmounts the activation energy of the reaction  by colliding (effective collision) more with oxygen. So, the reaction has an activation energy but the activation energy has been met and passed and hence the reaction is proceeding faster.

Increasing the temperature of a reaction is one of the ways of increasing the rate of a chemical reaction.

7 0
2 years ago
Consider the following reaction, which is spontaneous at room temperature. C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g) Is ΔS positive o
Ugo [173]

Answer:

∆H = negative and ∆S = positive.

Explanation:

The reaction given in the question is spontaneous at room temperature ,

hence ,

The the gibbs free energy , i.e. ,∆G will be negative for  spontaneous reaction

According to the formula ,

∆G = ∆H -T∆S

The value of ∆G can be negative , if  ∆H has a negative value and  ∆S has a positive value , because , T∆S  , has a negative sign .

Hence , the answer will be , ∆H = negative and ∆S = positive.

3 0
3 years ago
Identify the balanced equation for the following reaction:<br><br> SO2(g) + O2(g) → SO3(g)
sergiy2304 [10]

Answer:  The balanced equation for the given reaction is

2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g).

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side.

For example, SO_{2}(g) + O_{2}(g) \rightarrow SO_{3}(g)

Here, number of atoms on reactant side are as follows.

  • S = 1
  • O = 4

Number of atoms on product side are as follows.

  • S = 1
  • O = 3

To balance this equation, multiply SO_{2} by 2 on reactant side and multiply SO_{3} by 2. Hence, the equation will be re-written as follows.

2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)

Here, number of atoms on reactant side are as follows.

  • S = 2
  • O = 6

Number of atoms on product side are as follows.

  • S = 2
  • O = 6

Now, there are same number of atoms on both reactant and product side. So, this equation is balanced.

Thus, we can conclude that the balanced equation for the given reaction is 2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g).

3 0
2 years ago
A scuba diver knows that she needs 50.0mol of air for an upcoming dive. What size (volume) tank will she need to fill for this d
erica [24]

Answer:

1120 L.

Explanation:

Hello!

In this case, as no conditions of pressure of temperature are given for this problem, we can assume that the scuba diver dives at STP (1 atm and 273.15 K), which means that 1 mole of air would occupy a volume of 22.4 L.

In such a way, since she needs 50.0 moles of air, the following ratio is useful to compute the size (volume) of the tank she needs:

V_2=\frac{V_1*n_2}{n_1}

Thereby, we plug in to obtain:

V_2=\frac{22.4L*50.0mol}{1mol}\\\\V_2=1120 L

Best regards!

4 0
3 years ago
What are standards or attributes of a design that can be measured.
ankoles [38]

Explanation:

attribute of a person that often cannot be measured directly but can be assessed using numbers of indicators or manifest variables

4 0
3 years ago
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