1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bogdan [553]
3 years ago
8

Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. A mixtur

e of 41.0 g of magnesium and 175.0 g of iron(III) chloride is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete.
Chemistry
1 answer:
yuradex [85]3 years ago
6 0

<u>Answer:</u> The limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For magnesium:</u>

Given mass of magnesium = 41.0 g

Molar mass of magnesium = 24 g/mol

Putting values in equation 1, we get:

\text{Moles of magnesium}=\frac{41.0g}{24g/mol}=1.708mol

  • <u>For iron(III) chloride:</u>

Given mass of iron(III) chloride = 175.0 g

Molar mass of iron(III) chloride = 162.2 g/mol

Putting values in equation 1, we get:

\text{Moles of iron(III) chloride}=\frac{175g}{162.2g/mol}=1.708mol

The chemical equation for the reaction of magnesium and iron(III) chloride follows:

3Mg+2FeCl_3\rightarrow 3MgCl_2+2Fe

By Stoichiometry of the reaction:

3 moles of magnesium reacts with 2 moles of iron(III) chloride

So, 1.708 moles of magnesium will react with = \frac{2}{3}\times 1.708=1.114mol of iron(III) chloride

As, given amount of iron(III) chloride is more than the required amount. So, it is considered as an excess reagent.

Thus, magnesium is considered as a limiting reagent because it limits the formation of product.

Moles of excess reactant left (iron(III) chloride) = [1.708 - 1.114] = 0.594 moles

Now, calculating the mass of iron(III) chloride from equation 1, we get:

Molar mass of iron(III) chloride = 162.2 g/mol

Moles of iron(III) chloride = 0.594 moles

Putting values in equation 1, we get:

0.594mol=\frac{\text{Mass of iron(III) chloride}}{162.2g/mol}\\\\\text{Mass of iron(III) chloride}=(0.594mol\times 162.2g/mol)=96.35g

Hence, the limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.

You might be interested in
A train in Japan can travel 813.5 miles in 5 hours
Anastaziya [24]

Answer:

162.7miles/hr

Explanation:

Given parameters:

Distance covered by the train  = 813.5miles

Time taken  = 5hours

Unknown:

Speed of the train  = ?

Solution:

Speed is a physical quantity.

It is mathematically expressed as;

      Speed  = \frac{distance}{time}

So, input parameters and solve;

   Speed  = \frac{813.5}{5}  = 162.7miles/hr

8 0
3 years ago
Hurry!! Please
Vanyuwa [196]

c

Explanation:

pay attention in class next time bye hope it helps THE ANSWER IS C bye

7 0
2 years ago
Neopentyl alcohol, (ch3)3cch2oh, cannot be dehydrated to an alkene without rearrangement. what is the chief product of dehydrati
emmainna [20.7K]

Dehydration is removal of water.

In alcohols dehydration is α-β elimination or 1,2 elimination, it means the hydroxyl group will be removed from α-carbon while the hydrogen will be removed from near by carbon.

In case of neopentyl alcohol there is no β hydrogen present on the β carbon [as shown in figure].

The only possible way for it to undergo dehydration is by rearrangement.

The process or mechanism can be understood as:


so the chief product is 2-methylbut-2-ene



7 0
4 years ago
The pH of a 1.0M solution of butanoic acid HC4H7O2 is measured to be 2.41. Calculate the acid dissociation constant Ka of butano
Lubov Fominskaja [6]

Answer:

Ka = 1.52 E-5

Explanation:

  • CH3-(CH2)2-COOH ↔ CH3(CH2)2COO-  + H3O+

⇒ Ka = [H3O+][CH3)CH2)2COO-] / [CH3(CH2)2COOH]

mass balance:

⇒<em> C</em> CH3(CH2)2COOH = [CH3(CH2)2COO-] + [CH3(CH2)2COOH] = 1.0 M

charge balance:

⇒ [H3O+] = [CH3(CH2)2COO-]

⇒ Ka = [H3O+]²/(1 - [H3O+])

∴ pH = 2.41 = - Log [H3O+]

⇒ [H3O+] = 3.89 E-3 M

⇒ Ka = (3.89 E-3)² / ( 1 - 3.89 E-3 )

⇒ Ka = 1.519 E-5

3 0
3 years ago
The molecular formula of a compound is C7H14O7. what is the empirical formula​
nata0808 [166]
Empirical formula is the simplest way the molecular formula can be wrote so here 7 goes into all of these so it would be CH2O
6 0
2 years ago
Other questions:
  • A 45.9 g sample of a metal is heated to 95.2°c and then placed in a calorimeter containing 120.0 g of water (c = 4.18 j/g°c) at
    9·1 answer
  • What is the humidity if the dry-bulb is 10℃ and the wet-bulb is 6℃ (My subject is not really chemistry I had no other option)
    6·1 answer
  • When sugar is burned, water vapor and carbon dioxide are produced.
    11·2 answers
  • How many grams are there in 2.4 moles of CaCO3?
    9·1 answer
  • What gives bases their properties?
    12·1 answer
  • How many grams are there in a 3.5 moles of oxygen
    14·1 answer
  • Which form of energy does a car's engine convert into mechanical energy?
    5·1 answer
  • A cube has a height of 8 cm and a mass of 457 g. What is its density?
    5·1 answer
  • How many moles of oxygen are needed for the complete combustion of 12.6 moles of acetylene?
    15·1 answer
  • How many grams of NO can be made from 50 g of NH3?<br><br> 4 NH3 + 5 O2 → 6 H2O + 4 NO
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!